You have to add 5, 12, 21, and 19 and that will get you the answer of 57
J would equal -7.
I'm not exactly sure how I got that answer to be honest but I plugged -7 back in to make sure it was right.
-3(2*-7/3-6) = 32 is correct.
Answer:
c.) No, because Cp < 1
Step-by-step explanation:
Let us assume that there is centered in the process
and, the width is 2 times the specification
So, the width is
![= 2 \times 0.07](https://tex.z-dn.net/?f=%3D%202%20%5Ctimes%200.07)
= 0.14
Now capability index = Cp is
![= \frac{specification\ width}{6 \times standard\ deviation}\\\\= \frac{0.14}{6\times 0.04}](https://tex.z-dn.net/?f=%3D%20%5Cfrac%7Bspecification%5C%20width%7D%7B6%20%5Ctimes%20standard%5C%20deviation%7D%5C%5C%5C%5C%3D%20%5Cfrac%7B0.14%7D%7B6%5Ctimes%200.04%7D)
= 0.58333
And the capability index should be minimum 1 for the process
And as we can see that Cp is 0.58333 which is less than 1 so the machine is not able to perform the job
Hene, the correct option is c.
If you find the total amount of birds, which is 27... Then you read "Number of Geese to total birds"
15 to 27 or
15/27 or
15:27