<h2>
Initial velocity of the object = 31.4 m/s</h2>
Explanation:
If an object is thrown downward with an initial velocity of v₀, then the distance it travels is given by s = 4.9 t²+v₀t
Now an object is thrown downward from a cliff 400 m high and it travels 138.3 m in 3 sec. We need to find initial velocity of the object.
s = 4.9 t²+v₀t
138.3 = 4.9 x 3²+ v₀ x 3
3v₀ = 94.2
v₀ = 31.4 m/s
Initial velocity of the object = 31.4 m/s
Answer:
a)P=462.70 Pa
b)h = 0.047 m of water
Explanation:
Given that
Pressure ,
V= 100 km/h
V=27.77 m/s
The pressure P
P=462.70 Pa
We know that density of the water 
Lets height of the water column = h m
We know that
462.70 = 1000 x 9.81 h
h = 0.047 m of water
a)P=462.70 Pa
b)h = 0.047 m of water
Answer:
16 seconds
Explanation:
To do this you would set up the equation 75x=1200. Then you would divide 75 from both sides so you get x=16 or it takes 12 seconds for it to travel 1200 meters
A natural frequency of vibrations determined by the physical parameters of the vibrating object.
The velocity of the package after it has fallen for 3.0 s is 29.4 m/s
From the question,
A small package is dropped from the Golden Gate Bridge.
This means the initial velocity of the package is 0 m/s.
We are to calculate the velocity of the package after it has fallen for 3.0 s.
From one of the equations of kinematics for objects falling freely,
We have that,
v = u + gt
Where
v is the final velocity
u is the initial velocity
g is the acceleration due to gravity
and t is time
To calculate the velocity of the package after it has fallen for 3.0 s
That means, we will determine the value of v, at time t = 3.0 s
The parameters are
u = 0 m/s
g = 9.8 m/s²
t = 3.0 s
Putting these values into the equation
v = u + gt
We get
v = 0 + (9.8×3.0)
v = 0 + 29.4
v = 29.4 m/s
Hence, the velocity of the package after it has fallen for 3.0 s is 29.4 m/s
Learn more here: brainly.com/question/13327816
