Question

A small boat is moving at a velocity of 1.93 m/s when it is accelerated by a river current perpendicular to the initial direction of motion. If the acceleration of the current is 0.750 m/s2, what will be the new velocity of the boat after 19.3 s?

Answer 1

Answer:

16.405m/s

Explanation:

Given, initial velocity = u = 1.93m/s, acceleration = a = 0.750m/s2, time = t = 19.3s, final velocity = v= ?

Using the first equation of linear motion,

v = u + at

v = 1.93 + 0.750 x 19.3

v = 1.93 + 14.475

v = 16.405m/s

Answer 2

Answer:

v = 16.405 m/s  

Explanation:

The velocity v with a constant aceleration could be calculated by:

$v = v_0 +at$

where $v_0$ the initial velocity, a the aceleration of the current and t the time.

replacing the data:

$v = 1.93m/s +(0.75m/s^2)(19.3s)$

v = 16.405 m/s

So, the new velocity of the boat is 16.405m/s.