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Irina-Kira [14]
3 years ago
10

How do you know if an experimental result is acceptable or trustworthy? What gives you confidence that your data are trustworthy

?
Physics
1 answer:
Virty [35]3 years ago
6 0

Explanation:

For an experimental result to be considered acceptable, all relevant variables involved in the experiment must be taken into account, by isolating it, performing it under controlled conditions and modifying the conditions under which it takes place. This, with the objective of excluding alternative explanations in the analisis of the experimental data. Therefore, if these steps are followed appropriately, experimental data are trustworthy. The reliability of the experiment increases when it is replicated by other researchers and the same results are obtained.

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What is the particles instantaneous speed at t=16 sec
Ira Lisetskai [31]

It's  3.6 meters per second less than my speed was
at 4:19 PM last Tuesday.

Does that tell you anything ?
Why not ?

 
8 0
3 years ago
A 15x10^-6c charge is placed at the origin and a 9x10^-6C charge is placed on the x-axis at x=1.00m. where, on the x-axis is the
Harlamova29_29 [7]

The Electric field is zero at a distance 2.492 cm from the origin.

Let A be point where the charge 15\times10^-6 C is placed which is the origin.

Let B be the point where the charge 9\times 10^-6 C is placed. Given that B is at a distance 1 cm from the origin.

Both the charges are positive. But charge at origin is greater than that of B. So we can conclude that the point on the x-axis where the electric field = 0 is after B on x - axis.

i.e., at distance 'x' from B.

Using Coulomb's law, \frac{kQ_A^2}{d_A^2} = \frac{kQ_B^2}{d_B^2},

Q_A = 15\times 10^-6 C

Q_B=9\times10^-6C

d_A = 1+x cm

d_B=x cm

k is the Coulomb's law constant.

On substituting the values into the above equation, we get,

\frac{(15\times10^-6)^2}{(1+x)^2} =\frac{(9\times10^-6)^2}{x^2}

Taking square roots on both sides and simplifying and solving for x, we get,

1.67x = 1+x

Therefore, x = 1.492 cm

Hence the electric field is zero at a distance 1+1.492 = 2.492 cm from the origin.

Learn more about Electric fields and Coulomb's Law at brainly.com/question/506926

#SPJ4

3 0
1 year ago
Please help on this one?
butalik [34]

B. +Q, + W are the correct sign

7 0
3 years ago
Read 2 more answers
The two cyclists travel at the same speed on level ground. They approach a low hill and decide to coast up instead of hard pedal
Sergeeva-Olga [200]

Answer:

  • <u>Option-(E): </u>Bike B; its wheels have a smaller moment of inertia.                                                                                                                                                                                                                                                                              

Explanation:

  • The two cyclists travel at the same speed on level ground, as they approach a low hill and decide to coast up instead of hard pedaling. At the top of the hill, as bike "B" will have a larger speed, as compared to the bike "A".Due, to the effect of having smaller moment of inertia, I=m×r².
  • Having no friction nor air resistance, and all the wheels roll on the ground without slipping. While, the B have larger speed,v due to the fact that bike "B" will have a larger speed,"v" as compared to the bike "A".
3 0
3 years ago
The Earth has mass ME and average radius RE. The Moon has mass MM and the average distance from the center of mass of the moon t
marusya05 [52]

Answer:

Moment of inertia of Earth about its own axis is given as

I = 9.7 \times 10^{37} kg m^2

Explanation:

Since Earth is considered as solid sphere

So we will have

I = \frac{2}{5}M_eR_e^2

so we will have

I = \frac{2}{5}(5.97 \times 10^{24})(6.371 \times 10^6)^2

so we have

I = 9.7 \times 10^{37} kg m^2

3 0
3 years ago
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