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Art [367]
3 years ago
11

The graph is tied to the reading

Physics
1 answer:
AleksandrR [38]3 years ago
5 0
I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.

ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.

iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.

iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
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Jupiter and the other jovian planets are sometimes called "gas giants." in what sense is this term misleading?
shepuryov [24]
DEFINITION
The light stripes are regions of high clouds, and the dark stripes are regions where we can see down to deeper, darker clouds.

GOES WITH
Which of the following best why we see horizontal "stripes" in photographs of Jupiter and Saturn?
6 0
3 years ago
An object is dropped at a height of 12 m from the ground. How fast is it moving just before it hits the ground?
sp2606 [1]

The final speed of the object is 15.3 m/s

Explanation:

The object in the problem is moving by uniformly accelerated motion (it is in free fall), so we can use the following suvat equation:

v^2-u^2=2as

where

v is the final velocity

u is the initial velocity

a=g=9.8 m/s^2 is the acceleration of gravity (taking downward as positive direction)

s is the vertical displacement

For the object in this problem:

u = 0 (it starts from rest)

s = 12 m is the displacement of the object

Solving for v,

v=\sqrt{u^2+2as}=\sqrt{0+2(9.8)(12)}=15.3 m/s

Learn more about free fall motion here:

brainly.com/question/1748290

brainly.com/question/11042118

brainly.com/question/2455974

brainly.com/question/2607086

#LearnwithBrainly

6 0
3 years ago
Which are the products in the equation CH3SH + 4O2 → CO2 + SO2 +2H2O? Check all that apply. CH3SH, O2 ,CO2, SO2, H2O
VikaD [51]

Answer:

C D E is the answer

Explanation:

7 0
3 years ago
Read 2 more answers
What types of changes effect the sun’s energy output?
Greeley [361]

Answer:

the answer is A Cycles of solar flares and prominences heat and cool the layers below the sun’s surface

Explanation:

i took the quiz

3 0
3 years ago
The 2-Mg truck is traveling at 15 m/s when the brakes on all its wheels are applied, causing it to skid for 10 m before coming t
Scorpion4ik [409]

Answer:

constant horizontal force developed in the coupling C = 11.25KN

the friction force developed between the tires of the truck and the road during this time is 33.75KN

Explanation:

See attached file

8 0
4 years ago
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