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Art [367]
3 years ago
11

The graph is tied to the reading

Physics
1 answer:
AleksandrR [38]3 years ago
5 0
I. Positive acceleration increases velocity. Negative acceleration decreases velocity. runner A sped up until the finish line and then slowed to a stop.

ii. Zero a acceleration implies a constant, unchanging velocity not a zero velocity. runner B achieved some velocity prior to 8s and is moving and must slow down to reach a stop.

iii. None. No aspects of this reasoning are correct. Everything she says is wrong. See iv for what/why.

iv. The sign on acceleration denotes the direction of *change in velocity* not change in direction. The sign on velocity can denote change in direction but only “forward” or “reverse” along a particular path. Cardinal direction is not indicated, generally, by the sign on velocity. It may correspond to North/South situationally but it is not an built-in feature of velocity and its sign. For example, if you are traveling with positive velocity and turn left to continue your journey you still have a positive velocity in the new direction. In fact, if you turn left again, traveling in the opposite direction as the one you started with your velocity would still be positive… in the new direction. The velocity relative to original direction could be said to be negative but that would be a confusing way to describe a journey. Maybe if you stopped the vehicle and moved in reverse, you could meaningfully say velocity was negative.
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An automobile engine slows down from 4000rpm to 1100 rpm in 2.9 s . Calculate its angular acceleration, assumed constant.
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What is the formula for force?
Vitek1552 [10]
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4 years ago
CHEGG 42 mT magnetic field points due west. If a proton of kinetic energy 9 x 10-12 J enters this field in an upward direction,
alexdok [17]

Answer:

The  magnitude of the Force is  F = 697 *10^{-15}N  and the direction is South  

Explanation:

From the question we are told that

         The magnetic field point due west and since East point toward the positive x -axis(i)  then this magnetic field would be mathematically represented as

                \= B = 42(-i)mT = 42*10^{-3} (-i) T

Now from the question we are told that the kinetic energy is

             KE = 9*10^{-12}J

Now this kinetic energy can be mathematically represented as

                  KE = \frac{1}{2}mv^2

Where m is the mass of proton which has a general value of

           m = 1.67*10^{-27}kg

Now making the subject of the formula

                v = \sqrt{\frac{KE}{0.5 * m} }

Substituting values we have

               v = \sqrt{\frac{9*10^{-12}}{0.5 * 1.67*10^{-27}} }

                 = 10.37*10^7m/s

Now from the question we are told that proton is moving upward which is in the positive z direction so the velocity of the proton would be in the positive

So the velocity would be

            \= v = 10.37*10^{7} \r k \ m/s

Now the magnetic Force can be mathematically represented as

          \= F = q \= v * \=  B

Where q is the charge on the proton which has a general value of  q =1.6*10^{-19}C

Now substituting the value

          \= F = 1.6*10^{-19 } * (10.37 *10^7) \r k * (42 *10^{-3})(-i)

              = 697*10^{-15} J

Now according to Fleming's left hand rule the direction of the magnetic force is south toward the negative Y - direction (-j)

So the force can be denoted as

                 \= F = 697*10^{-15}(-j) N

             

             

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3 years ago
How much work is done when a book weighing 2.0 newtons is carried at constant velocity from one classroom to another classroom 2
san4es73 [151]
52 J


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