Answer : The pH of the resulting buffer is, 5.22
Explanation : Given,
First we have to calculate the moles of 
and,
The balanced chemical reaction is:
Moles of HA left = 0.117 mol - 0.08 mol = 0.037 mol
Moles of 
= 0.08 mol
The expression used for the calculation of 
is,
Now put the value of 
in this expression, we get:
Now we have to calculate the pH of buffer.
Using Henderson Hesselbach equation :
![pH=pK_a+\log \frac{[Salt]}{[Acid]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BSalt%5D%7D%7B%5BAcid%5D%7D)
![pH=pK_a+\log \frac{[A^-]}{[HA]}](https://tex.z-dn.net/?f=pH%3DpK_a%2B%5Clog%20%5Cfrac%7B%5BA%5E-%5D%7D%7B%5BHA%5D%7D)
Now put all the given values in this expression, we get:
Thus, the pH of the resulting buffer is, 5.22
Answer:
To separate an insoluble solid from a soluble solid: Mixing the mixture with water, filtering out the insoluble solid, and then evaporating the water to isolate the soluble solid.
Explanation:
Answer : The number placed in front of 
should be, three (3).
Explanation :
Balanced chemical reaction : It is defined as the number of atoms of individual elements present on reactant side must be equal to the product side.
The given unbalanced chemical reaction is,
This chemical reaction is an unbalanced reaction because in this reaction, the number of atoms of chloride and sulfate ion are not balanced.
In order to balanced the chemical reaction, the coefficient 3 is put before the , the coefficient 2 is put before the 
and the coefficient 3 is put before the 
.
Thus, the balanced chemical reaction will be,
Therefore, the number placed in front of should be, three (3).
Answers are Intermolecular and London dispersion
Percent to mass
Mass to mole
Divide by small
Multiply 'til whole
Assume 100 g of substance, then 82.2 g N and 17.8 g H.
82.2 g N * (1 mol/14.01 g N) = 5.86 mol N
17.8 g H * (1 mol/1.01 g H) = 17.6 mol H
Divide by the smallest mole
17.6 H / 17.6 = 1 H
5.86 N / 17.6 = 1/3 N
Multiply to make whole number ( x3 in this case)
3 x 1 H = 3H
3 x 1/3 N = 1 N
NH3
