Answer:
B
Step-by-step explanation:
So far, we know that:
∠D = ∠J.
And that:
DE:JK = 14:7 = 2:1
So, to prove that ΔDEF ~ ΔJKL by SAS, DF must be similar to JL, as those are the sides between the angle.
So:
DF:JL = 2:1.
Our answer is B.
Answer:
un-distribute the GCF of the two numbers.
16(1 + 3)
Distributing we get:
16(1) + 16(3)
16 + 48
Step-by-step explanation:
:)
Answer:
1) 36
b) 5
c) 3.0
Step-by-step explanation:
1) The recursive formula that defines the given sequence is

That means we keep adding 4 to the subsequent terms:
The sequence will be:
12,16,20,24,28,32,36,...
Therefore the seventh term is 36.
2) The sequence is recursively defined by;

This means, we have to keep subtracting 5 from the subsequent terms.
The sequence will be;
20,15,10,5,...
Therefore the fourth term is 5
3) The sequence is recursively defined by:
f(n+1)=f(n)+0.5
where f(1)=-1.5
This means that, the subsequent terms can be found by adding 0.5 to the previous terms.
The sequence will be:
-1.5,-1.0,-0.5,0,0.5,1,1.5,2.0,2.5,3.0,....
Therefore f(10)=3.0
Y would be 16,
y=kx
6=3k
2=k
y=2(8)
y=16