<span>1. Make y the subject
a) 4y=12x+18
y = 3x + 4.5
b) 2x=7-3y
3y = -2x + 7
y = -2/3x + 7/3
2.
a) what is the equation of the line which passes through both (-2,-4) and (6,16)
slope = (16 + 4)/(6 +2) = 20/8 = 2.5
y = mx + b
-4 =2.5(-2) +b
-4 = -5 +b
b = 1
equation
y = 2.5x + 1
b) what is the equation of the line perpendicular to y= 1/2X + 7 passing through point (3,9)
</span>y= 1/2X + 7
slope = 1/2
slope of line perpendicular = -2
passing through point (3,9)
y = mx + b
9 = -2 (3) + b
b = 15
equation
y = -2x + 15
Answer:
uh ok just give me the link to the question and I will see if I can help you :)
Step-by-step explanation:
The answer is 4/8 or 0.5(simplified)
We have that
3sin x+cos²<span>x=2
</span>3sin x+(1-sin²x)<span>=2
</span>-sin²x +3sin x=1
sin²x -3 sin x+1=0---------> up to here the procedure is correct
let
A=sin x
then
A²-3A+1=0
Group terms that contain the same variable, and move the
constant to the opposite side of the equation
(A²-3A)=-1
Complete the square. Remember to balance the equation
by adding the same constants to each side.
(A²-3A+2.25)=-1+2.25
Rewrite as perfect squares
(A-1.5)²=1.25
(+/-)(A-1.5)=1.12
first solution
(A-1.5)=1.12--------> A=1.12+1.5-----> A=2.62-----> sin x=2.62
second solution
-(A-1.5)=1.12----> -A+1.5=1.12----> A=1.5-1.12----> A=0.38---> sin x=0.38
the answer is
the equation was factored incorrectly
