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Law Incorporation [45]
3 years ago
10

HELPPP MEEE !!!!!!!!!

Mathematics
1 answer:
Sladkaya [172]3 years ago
4 0

Answer:

C. zero

Step-by-step explanation:

The system of equations has no solutions. You can solve this by plugging in the y value of the first equation into the second, giving you:

2(\frac{5}{2}x+2)=5x+8\\simplify:\\5x+4=5x+8\\you are left with -4=0, which is not a true statement

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Tammy is at the dentist's office waiting on her appointment. She notices that the 6-inch-long minute hand is rotating around the
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PART 1:55-21=35
             35/60=<span>.58333 
             360</span>×<span>.58333 =210 DEGREES
             </span><span>210*pi/180 = 3.665 RADIANS

PART 2: </span><span>(pi) x 2r x .58333 
              </span><span>3.14 x 12 x .58333 = 21.98 in 

PART 3: </span><span>5π inches = 5 x 3.14 = 15.708 inches / 6 in radius = 2.618 radians 

PART 4: </span><span>2.618 radians * 180/pi = 150° </span>
<span>             x coordinate = 6(cos 150°) = -5.196 </span>
<span>             y coordinate = 6(sin 150°) = 3 </span>
<span>             the coordinates would be (-5.196, 2)</span>
7 0
3 years ago
Read 2 more answers
What is the value of the expression below if y=5
Neko [114]

Answer:

25

Step-by-step explanation:

8*5=40

40+6=46

46-10=36

36-9=25

5 0
2 years ago
12.<br> 1/2(4x — 2) – 2/3(6x + 9) &lt;4
RSB [31]

Answer: x > -11/2

svdbhtdtgifubhonj

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2 years ago
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Find the value of k so that the
BaLLatris [955]

Answer:

gradient =  - 3 \\  - 3 =  \frac{(8 + 1)}{( - 2 - k)}  \\  3(2 + k) = 9 \\ 2 + k = 3 \\ k = 1

8 0
3 years ago
Please answer! I crossed out the ones you don’t have to complete.
Nina [5.8K]

Answer:

1. Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

5.  x^-6 = \frac{1}{x^6}

6. 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7. a^{-3}b^0c^4=\frac{c^4}{a^3}

Step-by-step explanation:

Question 1:

We need to rewrite the expression using exponents

5.a.b.b.5.c.a.b.5.b

We will first combine the like terms

5.5.5.a.a.b.b.b.b.c

Now, if we have 5.5.5 we can write it in exponent as: =5^{1+1+1}=5^3

a.a as a^{1+1}=a^2

b.b.b.b as: b^{1+1+1+1}=b^4

So, our result will be:

5^3a^2b^4c

Rewriting the expression 5.a.b.b.5.c.a.b.5.b using exponents we get: \mathbf{5^3a^2b^4c}

Question:

Rewrite using positive exponent:

The rule used here will be: a^{-1}=\frac{1}{a^1} which states that if we need to make exponent positive, we will take it to the denominator.

Applying thee above rule for getting the answers:

5) x^{-6} = \frac{1}{x^6}

6) 5^{-3}.3^{-1}=\frac{1}{5^3.3^1}

7) a^{-3}b^0c^4=\frac{b^0c^4}{a^3}

We know that b^0=1 so, we get

a^{-3}b^0c^4=\frac{b^0c^4}{a^3}=\frac{c^4}{a^3}

4 0
3 years ago
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