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Vesna [10]
2 years ago
12

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and th

e breadth of the pool?​
Mathematics
2 answers:
const2013 [10]2 years ago
4 0

Step by step:

Perimeter = Summation of all sides = AB+BC+CD+DA = 2x+2+x+2x+2+x=(6x+4)

⇒6x+4=154

⇒6x=154−4

⇒\frac{150}{6x}

⇒25=x

The breadth is x=25

The length of the rectangular pool = (2×25+2)=50+2=52m

<em>breadth </em>is 25 and the<em> length </em>is 52

Hope it helps!

Zinaida [17]2 years ago
4 0

\blue\star \rm\pink{ Question:}

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

\\  \\

\blue\star \rm\pink{ Given :}

  • Perimeter of swimming pool is 154 m
  • Length is 2m more than breadth

\\  \\

\blue\star \rm\pink{ To ~Find :}

  • Length of rectangular pool
  • Breadth of rectanglur pool

\\  \\

\blue\star \rm\pink{Let :}

  • Breadth of x
  • Length be (2 + 2x)

\\  \\

We know:-

\bigstar \boxed{ \rm perimeter \: of \: rextangle = 2(length +breadth)}

So:-

\\  \\

\dashrightarrow\sf perimeter \: of \: rextangle = 2(length +breadth) \\

\\  \\

\dashrightarrow\sf 154 = 2( 2 + 2x +x) \\

\\  \\

\dashrightarrow\sf 154 = 2( 2 + 3x) \\

\\  \\

\dashrightarrow\sf 154 = 2( 2 )+ 2(3x) \\

\\  \\

\dashrightarrow\sf 154 = 4+ 2(3x) \\

\\  \\

\dashrightarrow\sf 154 = 4+ 6x

\\  \\

\dashrightarrow\sf 154 - 4 =6x

\\  \\

\dashrightarrow\sf 150 =6x

\\  \\

\dashrightarrow\sf 6x = 150

\\  \\

\dashrightarrow\sf x = \dfrac{150}{6}

\\  \\

\dashrightarrow\sf x = \cancel \dfrac{150}{6}

\\  \\

\dashrightarrow\bf x =25

\\  \\

Let's Verify value of x:-

\\  \\

\dashrightarrow\sf 154 = 2( 2 + 2x +x) \\

put value of x in equation

\\  \\

\dashrightarrow\sf 154 = 2( 2 +  \{2 \times 25 \} +25) \\

\\  \\

\dashrightarrow\sf 154 = 2( 2 + 50+25) \\

\\  \\

\dashrightarrow\sf 154 = 2( 2 + 75) \\

\\  \\

\dashrightarrow\sf 154 = 2(77) \\

\\  \\

\dashrightarrow\bf 154 =154

\\  \\

\Large \bf\dag LHS = RHS \dag

Hence proved

\\  \\

Finally Let's find length and breadth of pool:-

\\  \\

To find breadth

➙ Breadth = x

➙ Breadth = 25 m

\\

To find length

➙ Length = 2 + 2x

➙ Length = 2 + 2(25)

➙ Length = 2 + 50

➙ Length = 52 m

____________________________________☆~

Cheers! all done. :)

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