Question

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?​

Answer 1

Step by step:

Perimeter = Summation of all sides = AB+BC+CD+DA = 2x+2+x+2x+2+x=(6x+4)

⇒6x+4=154

⇒6x=154−4

⇒$\frac{150}{6x}$

⇒25=x

The breadth is x=25

The length of the rectangular pool = (2×25+2)=50+2=52m

breadth is 25 and the length is 52

Hope it helps!

Answer 2

$\blue\star \rm\pink{ Question:}$

The perimeter of a rectangular swimming pool is 154 m. Its length is 2 m more than twice its breadth. What are the length and the breadth of the pool?

$\blue\star \rm\pink{ Given :}$

• Perimeter of swimming pool is 154 m
• Length is 2m more than breadth

$\blue\star \rm\pink{ To ~Find :}$

• Length of rectangular pool
• Breadth of rectanglur pool

$\blue\star \rm\pink{Let :}$

• Breadth of x
• Length be (2 + 2x)

We know:-

$\bigstar \boxed{ \rm perimeter \: of \: rextangle = 2(length +breadth)}$

So:-

$\dashrightarrow\sf perimeter \: of \: rextangle = 2(length +breadth)$

$\dashrightarrow\sf 154 = 2( 2 + 2x +x)$

$\dashrightarrow\sf 154 = 2( 2 + 3x)$

$\dashrightarrow\sf 154 = 2( 2 )+ 2(3x)$

$\dashrightarrow\sf 154 = 4+ 2(3x)$

$\dashrightarrow\sf 154 = 4+ 6x$

$\dashrightarrow\sf 154 - 4 =6x$

$\dashrightarrow\sf 150 =6x$

$\dashrightarrow\sf 6x = 150$

$\dashrightarrow\sf x = \dfrac{150}{6}$

$\dashrightarrow\sf x = \cancel \dfrac{150}{6}$

$\dashrightarrow\bf x =25$

Let's Verify value of x:-

$\dashrightarrow\sf 154 = 2( 2 + 2x +x)$

put value of x in equation

$\dashrightarrow\sf 154 = 2( 2 + \{2 \times 25 \} +25)$

$\dashrightarrow\sf 154 = 2( 2 + 50+25)$

$\dashrightarrow\sf 154 = 2( 2 + 75)$

$\dashrightarrow\sf 154 = 2(77)$

$\dashrightarrow\bf 154 =154$

$\Large \bf\dag LHS = RHS \dag$

Hence proved

Finally Let's find length and breadth of pool:-

To find breadth

➙ Breadth = x

➙ Breadth = 25 m

To find length

➙ Length = 2 + 2x

➙ Length = 2 + 2(25)

➙ Length = 2 + 50

➙ Length = 52 m

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Cheers! all done. :)