I feel like theirs probably one more answer to this help me know if it’s right or wrong I need to to pass!

At 10:30 AM, detectives discover a dead body in a room and measure its temperature at 27°C. One hour later, the body's temperatu

wolverine [178]

Answer:

The time of death was approximately 4 hours before 10:30 AM.

Explanation:

Temperature of the body when discovered by detective at 10:30 AM= 27°C

After discovery, Temperature of the body at 11.30 AM= 24.8°C

Change in time = ΔT = 1 hour

Rate of change of body temperature with respect to time :

$R=\frac{24.8^oC-27^oC}{1 hour}=-2.2^oC/hour$

Normal body temperature = 37°C

Change in time since death = ΔT'

$R=\frac{27^oC-37^oC}{\Delta T'}$

$-2.2^oC/hour=\frac{27^oC-37^oC}{\Delta T'}$

$\Delta T'=\frac{27^oC-37^oC}{-2.2^oC/Hour}=4.54 hour\approx 4 hours$

The time of death was approximately 4 hours before 10:30 AM.

4 0

4 years ago

Question:

ANEK [815]

Answer:

It states a fact about how nature works.

It often changes over time with new experiments and technology.

5 0

4 years ago

State five effect of heat matter

snow_lady [41]

When heat is added to a substance, the molecules and atoms vibrate faster. As atoms vibrate faster, the space between atoms increases. The motion and spacing of the particles determines the state of matter of the substance. ... When heat leaves all substances, the molecules vibrate slower.

I looked it up so this is googles answer

5 0

3 years ago

Suppose you take a 50gram ice cube from the freezer at an initial temperature of -20°C. How much energy would it take to complet

notsponge [240]

Answer:

The amount of energy required is $152.68\times 10^{3}Joules$

Explanation:

The energy required to convert the ice to steam is the sum of:

1) Energy required to raise the temperature of the ice from -20 to 0 degree Celsius.

2) Latent heat required to convert the ice into water.

3) Energy required to raise the temperature of water from 0 degrees to 100 degrees

4) Latent heat required to convert the water at 100 degrees to steam.

The amount of energy required in each process is as under

1) $Q_1=mass\times S.heat_{ice}\times \Delta T\\\\Q_1=50\times 2.05\times 20=2050Joules$

where

$'S.heat_{ice}$ ' is specific heat of ice = $2.05J/^{o}C\cdot gm$

2) Amount of heat required in phase 2 equals

$Q_2=L.heat\times mass\\\\\therefore Q_{2}=334\times 50=16700Joules$

3) The amount of heat required to raise the temperature of water from 0 to 100 degrees centigrade equals

$Q_3=mass\times S.heat\times \Delta T\\\\Q_1=50\times 4.186\times 100=20930Joules$

where

$'S.heat_{water}$ ' is specific heat of water= $4.186J/^{o}C\cdot gm$

4) Amount of heat required in phase 4 equals

$Q_4=L.heat\times mass\\\\\therefore Q_{4}=2260\times 50=113000Joules\\\\$ $\\\\\\\\$ Thus the total heat required equals $Q=Q_{1}+Q_{2}+Q_{3}+Q_{4}\\\\Q=152.68\times 10^{3}Joules$

5 0

3 years ago

Why are some areas in Europe seeing a partial solar eclipse while others are observing a total solar eclipse?

GuDViN [60]

Answer:

Objects between the source and observer produce possible shadows known as the umbra and the penumbra.

The umbra is a totally shadowed area, no light travels directly from the source to the observer.

The penumbra is a partially shadowed are where some of the source light travels directly to the observer an some of the source light is blocked from the observer (the object blocking the light is not a point object).

The question apparently refers to the differences seen by the observers.

5 0

3 years ago