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ANTONII [103]
3 years ago
13

uniform ladder of length 6.0 m and weight 300 N leans against a frictionless vertical wall. The foot of the ladder isplaced 3.0

m from the base of the wall. What must be the magnitude of the force of static friction supplied by the floorto keep the ladder from slipping
Physics
1 answer:
olganol [36]3 years ago
3 0

Answer:

Fx1 (6 m) sin 60 = 300 (3 m) cos 60  balancing torques about floor

Fx1 = 900 * 1/2 / 5.20 = 86.6 N  this is the horizontal force that must be supplied by the wall to balance torques about the floor

This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.

Fx1 = Fx2 = 86.6 N

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Answer:

Properties of matter

Explanation:

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The correct expression for the maximum speed of the object during its motion is \frac{FT}{m}.

<h3>Maximum speed of the object</h3>

The maximum speed of the object is determined using the following formulas;

v(max) = Aω

where;

  • A is the amplitude of the motion
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The maximum speed of the object can also be obtained from the maximum net force on the object,

F = ma

where;

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F = m(v/t)

mv = Ft

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Thus, the correct expression for the maximum speed of the object during its motion is \frac{FT}{m}.

Learn more about maximum speed here: brainly.com/question/4931057

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