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ANTONII [103]
3 years ago
13

uniform ladder of length 6.0 m and weight 300 N leans against a frictionless vertical wall. The foot of the ladder isplaced 3.0

m from the base of the wall. What must be the magnitude of the force of static friction supplied by the floorto keep the ladder from slipping
Physics
1 answer:
olganol [36]3 years ago
3 0

Answer:

Fx1 (6 m) sin 60 = 300 (3 m) cos 60  balancing torques about floor

Fx1 = 900 * 1/2 / 5.20 = 86.6 N  this is the horizontal force that must be supplied by the wall to balance torques about the floor

This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.

Fx1 = Fx2 = 86.6 N

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Suppose that instead of a long straight wire, a shortstraight wire was used. The distance from the wire to thepoint that the mag
vichka [17]

Answer:

Thus, if field were sampled at same distance, the field due to short wire is greater than field due to long wire.

Explanation:

The magnetic field, B of long straight wire can be obtained by applying ampere's law

B= \frac{\mu_0 I}{2\pi r}

I is here current, and r's the distance from the wire to the field of measurement.

The magnetic field is obviously directly proportional to the current wire. From this expression.

As the resistance of the long cable is proportional to the cable length, the short cable becomes less resilient than the long cable, so going through the short cable (where filled with the same material) is a bigger amount of currents. If the field is measured at the same time, the field is therefore larger than the long wire because of the short wire.

4 0
3 years ago
There are planets in the universe without a parent star. most all stars have planets. most stars are binary. true false
Ghella [55]

True : yes there are planets in the universe without a parent star called

rogue planets.

False :  most stars are not binary

What is rogue planets ?

planets which do not orbits the planetary system is known as roque planets. For example, pluto. Rogue planets can be smaller and bigger than jupiter too.

Free-floating planets or rogue planets without orbits around stars may also harbor life, some scientists believe. Due to the gravitational effects of giant planets within their system, these planets get kicked out of their system like any other planets formed around stars.

no most stars are not binary, binary which means two stars orbit around the common center and approximately only 40 binary stars have been found till not in our solar system.

Read more about solar system at:

brainly.com/question/12075871

#SPJ4

5 0
1 year ago
Help me with number 3 and 4 pleaseeeeeeeee
Andrej [43]

i think its b cause if you were talking about ice it freezes the melts the evaporates to gas

6 0
3 years ago
Read 2 more answers
A tin atom has 50 electrons. Electrons in the ________ subshell experience the lowest effective nuclear charge.
Alexus [3.1K]

Answer:

5p

Explanation:

We are given that a tin has 50 electrons.

We have to find in which subshell electrons experience the lowest effective nuclear charge.

We know that the electron in outermost shell experience the lowest effective nuclear charge.

Electronic configuration is given by

50=1s^22s^22p^63s^23p^64s^23d^{10}4p^65s^24d^{10}5p^2

Outer most sub-shell is 5p. Therefore, 5p subshell experience the lowest effective nuclear charge because the distance of 5p sub-shell is large from nucleus.

Answer: 5p

5 0
3 years ago
How much heat is required to raise 100 grams of water (c= 4.18) by 5 degrees Celsius?
Andrei [34K]

Answer:

Heat capacity, Q = 2090 Joules.

Explanation:

Given the following data;

Mass = 100 grams

Specific heat capacity = 4.18 J/g°C.

Temperature = 5°C

To find the quantity of heat required;

Heat capacity is given by the formula;

Q = mct

Where;

Q represents the heat capacity or quantity of heat.

m represents the mass of an object.

c represents the specific heat capacity of water.

t represents the temperature of an object.

Substituting into the formula, we have;

Q = 100*4.18*5

Heat capacity, Q = 2090 Joules.

7 0
3 years ago
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