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ANTONII [103]
3 years ago
13

uniform ladder of length 6.0 m and weight 300 N leans against a frictionless vertical wall. The foot of the ladder isplaced 3.0

m from the base of the wall. What must be the magnitude of the force of static friction supplied by the floorto keep the ladder from slipping
Physics
1 answer:
olganol [36]3 years ago
3 0

Answer:

Fx1 (6 m) sin 60 = 300 (3 m) cos 60  balancing torques about floor

Fx1 = 900 * 1/2 / 5.20 = 86.6 N  this is the horizontal force that must be supplied by the wall to balance torques about the floor

This is also equal to the static force of friction that must be applied at the point of contact with the floor to balance forces in the x-direction.

Fx1 = Fx2 = 86.6 N

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What is the equivalent resistance of the circuit?
podryga [215]

Answer:

Option D. 5.45 Ω

Explanation:

From the question given above, the following data were obtained:

Resistance 1 (R₁) = 10 Ω

Resistance 2 (R₂) = 20 Ω

Resistance 3 (R₃) = 30 Ω

Voltage (V) = 120 V

Equivalent resistance (R) =?

The equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/20 + 1/30

Find the least common multiple (lcm) of 10, 20 and 30. The result is 60

Divide 60 by each of the denominators and multiply by their numerators respectively. We have:

1/R = (6 + 3 + 2)/60

1/R = 11/60

Invert

R = 60/11

R = 5.45 Ω

Thus, the equivalent resistance in the circuit is 5.45 Ω

8 0
3 years ago
Question 3 of 15
4vir4ik [10]

Answer:

A. Trial and error

Explanation:

Trial and error method is a method adopted when trying to solve a quadratic equation. This equation is mostly the balancing of the right hand side and the left hand side in-order to form a unique point or to equate to zero when one is subtracted from the other. <em>In trail and error method, the coefficients is used to determine when the actual equation is balanced and the likely answer it should be if the equation is expanded through multiplication method.</em>

5 0
3 years ago
A coil lies flat on a level table top in a region where the magnetic field vector points straight up. The magnetic field suddenl
Leto [7]

Answer:

a) counterclockwise

Explanation:

The Lenz's Law establish that the direction of the induced current is in an opposite direction, in comparison with the change od the magnetic flux.

\epsilon=-\frac{d\Phi_{B}}{dt}

Specifically, if the flux decreases the induced current is in a counterclockwise direction, if increases, the direction is in a clockwise direction.

HOPE THIS HELPS!!

5 0
3 years ago
Why is physics important to everyone? Describe 5 applications of physics in everyday life.
Sedaia [141]

1. Communication

   In early ages people were using letters to communicate between them. Now days instantly we can call one person from anywhere, these are based on optical fiber communication and it is an application of physics.

2. Transportation

  We can travel from place to anther place by aeroplane , these technologies are introduced after advancement in physics.

3. Construction

 Earlier people used to stay in small houses, now days apartments with many number of storeys are built by considering all the forces coming on the structure.

4. Medical Department

 The invention of many equipment increased the health of humans.

5. Weather forecasting

 The prediction of weather considering all the available factors, prediction of natural disasters all are application of physics.

4 0
3 years ago
A cylindrical tungsten filament 16.0 cm long with a diameter of 1.00 mm is to be used in a machine for which the temperature wil
KonstantinChe [14]

Answer:

Explanation:

Resistance of the tungsten wire

R = resistivity x length / cross sectional area

= \frac{5.25\times10^{-8}\times16\times10^{-2}}{3.14\times(.5\times10^{-3})^2}

= 107 x 10⁻⁴ ohm

Resistance at 120 degree can be obtained from the following formula

R_t = R_0( 1 + \alpha\times t )

R_t = 107\times10^{-4}( 1 + .0045\times 100)

= 155.15 x 10⁻⁴ ohm

= 160 x 10⁻⁴ ohm ( rounding off to two syg fig )

current = 12.5

potential diff = 12.5 x 155.15 x 10⁻⁴ V

=  0 .1939 V

= .19 V

required electric field = potential diff / length of wire

= .1939 / 16 x 10⁻²

= 1.2 N / C

4 0
3 years ago
Read 2 more answers
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