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MA_775_DIABLO [31]
3 years ago
13

The officers of a high school senior class are planning to rent buses and vans for a class trip. Each bus can transport 6363 ​st

udents, requires 88 ​chaperones, and costs ​$1 comma 2001,200 to rent. Each van can transport 77 ​students, requires 1​ chaperone, and costs ​$8080 to rent. Since there are 567567 students in the senior class that may be eligible to go on the​ trip, the officers must plan to accommodate at least 567567 students. Since only 8080 parents have volunteered to serve as​ chaperones, the officers must plan to use at most 8080 chaperones. How many vehicles of each type should the officers rent in order to minimize the transportation​ costs? What are the minimal transportation​ costs?
Mathematics
1 answer:
attashe74 [19]3 years ago
3 0

Answer:

  • 1 bus, 72 vans
  • $6960 is the minimum cost

Step-by-step explanation:

A bus costs over $19 per student; a van costs less than $12 per student. The required number of students could be transported by 81 vans, but that requires 81 chaperones.

Since there are only 80, and a bus requires fewer chaperones per student, we can reduce the number of required chaperones to an acceptable level by employing one bus. 1 bus replaces 9 vans, and requires 1 less chaperone than 9 vans.

The minimum cost is 1 bus and 72 vans. That cost is $1200 +72×$80 = $6960.

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The value of H is half the value of G ( G = 2/3 )
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Step-by-step explanation:

i found it by dividing the value of G on 2

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2 years ago
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3 years ago
Mr. Blue drove from Allston to Brockton, a distance of 105 miles. On his way back, he increased his speed by 10 mph. If the jour
andrew-mc [135]

Answer:

His original speed was 60 mph.

Step-by-step explanation:

The average speed formula is shown below:

speed = distance / time

For the first leg of the trip Mr. Blue drove at a speed of "x" mph, for a distance of 105 miles, therefore the time that took to complete the trip is:

time 1 = distance / speed

time 1 = 105 / x h

On the second leg of the trip Mr. Blue drove faster at a speed of "x + 10" mph, so the time it took him to complete the trip was 15 minutes less, therfore:

time 2 = time1 - (15/60) = (105/x) - 0.25 = (105 - 0.25*x)/x h

Applyint the time and speed from the second leg to the average speed formula we have:

x + 10 = {105/[(105 - 0.25*x)/x]}

x + 10 = 105*x/(105 - 0.25*x)

(x + 10)*(105 - 0.25*x) = 105*x

105*x + 1050 -0.25*x² - 2.5*x = 105*x

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Since his speed couldn't be negative the only possible value was 60 mph.

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3 years ago
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