Question

The graph of the function g(x) contains the point (4,1/5). What point must be on the graph of y=5g(x+1)?

Answer 1

The point that must be on the graph of:

$y=5g(x+1)$

is:

$(3,1)$

Explanation:

In this case, we have the following function:

$g(x)$

This function contains the point:

$(4,\frac{1}{5})$

In other words:

$For \ the \ point \ (4,\frac{1}{5}) \rightarrow x=4 \ and \ y=\frac{1}{5} \\ \\ So: \\ \\ y=g(x) \ and \ g(4)=\frac{1}{5} \\ \\ \\ For \ y=5g(x+1) \\ \\ We \ know \ g(4) \ So: \\ \\ x+1=4 \ \therefore x=3 \\ \\ Then: \\ \\ y=5g(3+1) \\ \\ y=5g(4) \\ \\ y=5(\frac{1}{5}) \\ \\ y=1$

So the point that must be on the graph of:

$y=5g(x+1)$

is:

$(3,1)$

Learn more:

Functions: brainly.com/question/12891789

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