All categories

3 years ago

If f(x)=x^2 - 3 and f(a)=46, what is the value of a? explain

1 answer:

8 0

You are trying to find what x to put into f(x) to get out 46. To do this, solve the following equation.
$x^{2} -3 = 46$
$x^2 = 49$
$x^2 = \sqrt{49}$
Therefore x = 7 or x = -7

-7, 7

You might be interested in

PLEASE HELP ASAP DUE IN 3 MINUTES

Inga [223]

Answer:

1728 in²

Step-by-step explanation:

For the area of B, you need to find the length and width (height and base, whatever you want to call it).

For the height, you would need to do: 144 - 36 - 24 - 36 = 48 inches

For the base, you would need to do: 60 - 24 = 36 inches

Now you multiply the base and height to get the area: 48 x 36 = 1728 in²

7 0

2 years ago

Select all the statements that are true for any value of x

Goryan [66]

Answer:

A, C, E, F

Explanation:

equal on both sides

6 0

2 years ago

Wilma and Fred rode their bikes toward each other from points on a straight road 32 miles apart. If Fred rode 3 miles per hour f

Firdavs [7]

Answer:

wilma is 22.5 mph

fred is 25.5 mph

Step-by-step explanation:

Time:40 minutes, or 2/3 hours

Speed:

Fred:x+3

Wilma: x

Distance:32 miles

2/3(x+x+3)=32

2/3(2x+3)=32

1 1/3x+2=32

4/3x=30

x=22.5

wilma is 22.5 mph

fred is 22.5+3= 25.5 mph

6 0

3 years ago

Multiply the polynomials. (4x- + 4x + 6)(7x + 5)

SashulF [63]

$\implies {\blue {\boxed {\boxed {\purple {\sf { \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30}}}}}}$

$\large\mathfrak{{\pmb{\underline{\red{Step-by-step\:explanation}}{\red{:}}}}}$

$(4 {x}^{2} + 4x + 6)(7x + 5)$

$= \: 7x(4 {x}^{2} + 4x + 6) + 5(4 {x}^{2} + 4x + 6)$

$= \: 28 {x}^{3} + 28 {x}^{2} + 42x + 20 {x}^{2} + 20x + 30$

Combining like terms, we have

$= \: 28 {x}^{3} + (28 {x}^{2} + 20 {x}^{2} ) + (42x + 20x) + 30$

$= \: 28 {x}^{3} + 48 {x}^{2} + 62x + 30$

$\large\mathfrak{{\pmb{\underline{\orange{Mystique35 }}{\orange{❦}}}}}$

3 0

3 years ago

What ordered pair is closest to a local minimum of the

grin007 [14]

Answer:

(2,1) aka D

Step-by-step explanation:

6 0

3 years ago