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Mazyrski [523]
3 years ago
12

Help please :) show work if possible

Mathematics
1 answer:
Vadim26 [7]3 years ago
3 0

Answer:

they are both yes and i dont know how i would show work on this

Step-by-step explanation:

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Pls help duhdiudhuod
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Answer:

X. y

10. $7

24. $14

38. $ 21

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Travis traveled 315 miles in 5 hours. What is his unit rate of speed in miles per hour?
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Which graph best represents the function f(x)=2x ?
yan [13]

Answer:

B

Step-by-step explanation:

The best - well, only way- is to check a few points.

Namely -1 (unless your eyesight is really poor!), 0, 1, 2, and 3.

f(x) = 2^x\\f(-1) = 2^-^1 = \frac12\\f(0) =2^0 =1\\f(1)= 2^1=2\\f(2)=2^2=4\\f(3)=2^3= 8

Now you can mark all these points in each graph (well, you could if they were on paper and not on a screen) and see which one of the lines passes through all of them. Spoiler alert, it's the B graph.

A represents 2(2^x) = 2^{x+1}, B is the one you want, C is \frac{2^x}2 = 2^{x-1} and D looks like 4^x = 2^2^x

3 0
2 years ago
I NEED HELP WITH THESE #'S [20pts❤️]
lara31 [8.8K]
Okay, this is a written proof so what you have to do is list the steps. I am going to try my best to solve this problem...

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3 years ago
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If you invest $100,000 in an account earning 8% interest compounded annually, how long will it take until the account holds $300
Monica [59]

We have been given that you invest $100,000 in an account earning 8% interest compounded annually. We are asked to find the time it will take the amount to reach $300,000.

We will use compound interest formula to solve our given problem.

A=P(1+\frac{r}{n})^{nt}, where,

A = Final amount after t years,

P = Principal amount,

r = Annual interest rate in decimal form,

n = Number of times interest is compounded per year,

t = Time in years.  

8\%=\frac{8}{100}=0.08

300,000=100,000(1+\frac{0.08}{1})^{1\cdot t}

300,000=100,000(1.08)^{t}

\frac{300,000}{100,000}=\frac{100,000(1.08)^{t}}{100,000}

3=(1.08)^{t}

(1.08)^{t}=3

Let us take natural log on both sides of equation.

\text{ln}((1.08)^{t})=\text{ln}(3)

Using natural log property \text{ln}(a^b)=b\cdot \text{ln}(a), we will get:

t\cdot \text{ln}(1.08)=\text{ln}(3)

\frac{t\cdot \text{ln}(1.08)}{\text{ln}(1.08)}=\frac{\text{ln}(3)}{\text{ln}(1.08)}

t=\frac{1.0986122886681097}{0.0769610411361283}

t=14.274914586

Upon rounding to nearest tenth of year, we will get:

t\approx 14.3

Therefore, it will take approximately 14.3 years until the account holds $300,000.

7 0
3 years ago
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