Question: calculate the measure of angle JKL, i.e. mJKM+mMKL
Answer:
78°
Step-by-step explanation:
angle JKM is a tangent-chord intersection angle and equals half of the intercepted arc KM of 76°. Thus
mJKM = 76/2 = 38°
angle MKL is an inscribed angle and equals half of the intercepted arc ML of 80°, Thus
mMKL = 80/2 = 40°.
Therefore angle JKL = 38°+40° = 78°.
Answer:
u = 10
Explanation:
The slope of the lone can be calculated as follows:
slope = (y2-y1) / (x2-x1)
We are given:
slope = -4/3
point (10,6) representing (x1,y1)
point (7,u) representing (x2,y2)
Substitute with the givens in the above equation and solve for u as follows:
slope = (y2-y1) / (x2-x1)
-4/3 = (u-6) / (7-10)
-4/3 = (u-6) / -3
4/3 = (u-6) / 3
3*4 = 3*(u-6)
4 = u-6
u = 4+6
u = 10
Hope this helps :)
Answer:
Step-by-step explanation:
según el número de animales
Answer:
(1, 1 )
Step-by-step explanation:
Given the 2 equations
2x + 3y = 5 → (1)
7x - 5y = 2 → (2)
Multiplying (1) by 5 and (2) by 3 and adding will eliminate the y- term
10x + 15y = 25 → (3)
21x - 15y = 6 → (4)
Add (3) and (4) term by term to eliminate y
31x = 31 ( divide both sides by 31 )
x = 1
Substitute x = 1 into either of the 2 equations and evaluate for y
Substituting into (1)
2(1) + 3y = 5
2 + 3y = 5 ( subtract 2 from both sides )
3y = 3 ( divide both sides by 3 )
y = 1
Solution is (1, 1 )
