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3 years ago

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What is the reciprocal of 7/11 in simpliest form

1 answer:

Leona [35]3 years ago

8 0

Answer:

11/7is your <em>answer</em><em> </em><em>.</em><em>.</em><em>.</em><em>.</em>

Step-by-step explanation:

hope its help you

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(a) Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the powe

Fofino [41]

Answer:

a) $\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}$

b) See Below for proper explanation

Step-by-step explanation:

a) The objective here is to Use the power series expansions for ex, sin x, cos x, and geometric series to find the first three nonzero terms in the power series expansion of the given function.

The function is $e^x + 3 \ cos \ x$

The expansion is of $e^x$ is $e^x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ...$

The expansion of cos x is $cos \ x = 1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...$

Therefore; $e^x + 3 \ cos \ x = 1 + \dfrac{x}{1!}+ \dfrac{x^2}{2!}+ \dfrac{x^3}{3!} + ... 3[1 - \dfrac{x^2}{2!}+ \dfrac{x^4}{4!}- \dfrac{x^6}{6!}+ ...]$

$e^x + 3 \ cos \ x = 4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} + \dfrac{x^3}{3!}+ ...$

Thus, the first three terms of the above series are:

$\mathbf{4 + \dfrac{x}{1!}- \dfrac{2x^2}{2!} ...}$

b)

The series for $e^x + 3 \ cos \ x$ is $\sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!} + 3 \sum \limits^{\infty}_{x=0} ( -1 )^x \dfrac{x^{2x}}{(2n)!}$

let consider the series; $\sum \limits^{\infty}_{x=0} \dfrac{x^x}{n!}$

$|\frac{a_x+1}{a_x}| = | \frac{x^{n+1}}{(n+1)!} * \frac{n!}{x^x}| = |\frac{x}{(n+1)}| \to 0 \ as \ n \to \infty$

Thus it converges for all value of x

Let also consider the series $\sum \limits^{\infty}_{x=0}(-1)^x\dfrac{x^{2n}}{(2n)!}$

It also converges for all values of x

7 0

3 years ago

Find the value of x

motikmotik

Answer:

$5x - 3 + 47 - x = 180 \\ 4x + 44 = 180 \\ 4x = 136 \\ x = 34$

7 0

2 years ago

Use substitution to solve each system of equations.<br> y = 5x -2<br> 3 x- 5y =4

Nezavi [6.7K]

x = 3/11
y = -7/11

Step-by-step explanation:

y = 5x - 2…Equation 1

3x - 5y = 4…Equation 2

Subtitute value of y to Equation 2 :

3x - 5(5x - 2) = 4

3x - 25x + 10 = 4

-22x + 10 = 4

10 - 4 = 22x

6 = 22x

6/22 = x

<u>3/11 = </u><u>x</u>

Subtitute value of x to one of Equation :

for example Equation 2…

3x - 5y = 4

3(3/11) - 5y = 4

9/11 - 5y = 4

9/11 - 4 = 5y

(9 - 44)/11 = 5y

(-35)/11 = 5y

(-35)/11 × 1/5 = y

<u>-7/11 = y</u>

7 0

2 years ago

Read 2 more answers

Need help ASAP please!! Thank you!

deff fn [24]

What’s the question

6 0

2 years ago

ILL GIVE BRAINIEST TO WHOEVER IS CORRECT!! PLEASE HELP ASAP!!

kogti [31]

Answer:

Step-by-step explanation:

3 0

3 years ago