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DIA [1.3K]
3 years ago
6

Name the line and plane shown in the diagram.

Mathematics
2 answers:
dem82 [27]3 years ago
8 0
The correct answer would be c
Mekhanik [1.2K]3 years ago
4 0

the answer is PQ and plane SP

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32 is 56% of what number?
prisoha [69]

Answer:

About 57.14285714, or 57 1/7 (400/7)

Step-by-step explanation:

Suppose the answer is x. This would mean that x multiplied by 0.56 (56%) would equal 32. To isolate x, you would have to divide both sides by 0.56, making the answer 32/0.56, or About 57 and 1/7

3 0
3 years ago
A hat contains four balls. The balls are numbered 2, 4, 4, and 5. One ball is randomly selected
lorasvet [3.4K]

Answer:

C) If the sum is 6, a small cone will be ordered . the sum is 7 or 8 , a medium cone will be ordered. If the sum is 9, a large cone will be ordered

Step-by-step explanation:

If the sum is a 6: (2+4) or (4+2)

P(6) = (2 is first picked)(4 is picked next) + (4 is first picked)(2 is picked next)

P(6)= (\frac{1}{4})(\frac{2}{3}) +(\frac{2}{4})(\frac{1}{3})

P(6) =\frac{2}{12} + \frac{1}{6} = \frac{1}{3}

If the sum is a 7: (2+5) or (5+2)

P(7) = (2 is first picked)(5 is picked next) + (5 is first picked)(2 is picked next)

P(7)= (\frac{1}{4})(\frac{1}{3}) +(\frac{1}{4})(\frac{1}{3})

P(7) =\frac{1}{12} + \frac{1}{12} = \frac{1}{6}

If the sum is a 8: (4+4)

P(8)= (\frac{2}{4})(\frac{1}{3})=\frac{1}{6}

If the sum is a 9: (4+5) or (5+4)

P(9) = (4 is first picked)(5 is picked next) + (5 is first picked)(4 is picked next)

P(9)= (\frac{2}{4})(\frac{1}{3}) +(\frac{1}{4})(\frac{2}{3})

P(9) =\frac{1}{6} + \frac{1}{6} = \frac{1}{3}

P(6) =  \frac{1}{3}

P(7) =  \frac{1}{6} ;P(8) =  \frac{1}{6}

P(7) or P(8) = \frac{1}{6} + \frac{1}{6} = \frac{1}{3}

P(9) =  \frac{1}{3}

Therefore, if the sum is 6, a small cone will be ordered . the sum is 7 or 8 , a medium cone will be ordered. If the sum is 9, a large cone will be ordered

8 0
3 years ago
Pls help<br><br> 2 Question
maw [93]

Answer:

1.320  ,

2.322

Step-by-step explanation:

1. Given that,

a+1/a=18

now,

(a- 1/a)² =( a+1/a)² - 4a. 1/a         [(a- b)² =( a+b)² - 4a. b  ]

           =18² - 4 . 1                      [as, a . 1/a =1 ]    

            =324 - 4

            =320

2.Given that,

a - 1/a=4

now,

a⁴+(1/a)⁴

=(a²)² + (1/a²)²                             [a⁴=(a²)² & (1/a)⁴=(1/a²)²]  

=(a²+1/a²) ²- 2 a². (1/a²)                [a²+b²=(a+b)²-2ab]

=[(a - 1/a)² +2.a. 1/a]² - 2               [a²+b²=(a-b)²+2ab]

=[4²+2]² -2

=[16+2]²-2

=18²-2

=324-2

=322

5 0
3 years ago
Can someone please help me with this please quick
Dima020 [189]
5(5c-1) 
                                         
.................................................................................................
6 0
3 years ago
Recent crime reports indicate that 3.8 motor vehicle thefts occur each minute in the United States. Assume that the distribution
Jet001 [13]

Answer:

a) The probability that 4 thefts occur in a minute is 0.19

b) The probability there are three or more thefts in a minute is 0.735

c) The probability there is one or less thefts in a minute is 0.106

Step-by-step explanation:

The formula for an event with a Poisson probability distribution is given by:

P (n events in an interval) = λⁿe^(-λ) / n!    where λ is the average number of events in the interval.

In this problem we have λ = 3.8

<u>a) Calculate the probability exactly four thefts occur in a minute.</u>

λ = 3.8 n = 4

P( 4 thefts occur) = 3.8⁴e⁻³⁻⁸ / 4! = 4.665/24 = 0.194

The probability that 4 thefts occur in a minute is 0.194

<u>b)What is the probability there is one or less thefts in a minute?</u>

P(0 thefts occur) + P(1 thefts occur)  (n = 0, n = 1)

3.8⁰e⁻³⁻⁸/0! + 3.8¹e⁻³⁻⁸/1! = e⁻³⁻⁸ + 3.8 e⁻³⁻⁸ = 0.022 + 0.084 = 0.106

The probability that there is one or less thefts in a minute is 0.106

<u />

<u>c) What is the probability there are three or more thefts in a minute?</u>

This is equal to the probability of (1 - the probability of 0, 1 or 2 thefts occurring)  but we already know that the probability of one or less thefts occurring is 0.106 so we only need the probability that there are 2 thefts in one minute

P(2 thefts in one minute) = 3.8²e³⁻⁸ / 2! = 14.44 (0.022)/2 = 0.159

Therefore, the probability that there are three or more thefts in a minute is

1 - (P(0) + P(1) + P(2)) = 1 - (0.022 +0.084 + 0.159) = 1 - 0.265 = 0.735

8 0
3 years ago
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