Answer:
Option (2).
Step-by-step explanation:
It is given in the question,
ΔLMN is a right triangle with base LM = 3a units
Hypotenuse MN = 5a
By applying Pythagoras theorem in ΔLMN,
MN² = LM² + NM²
(5a)² = (3a)² + MN²
25a² - 9a² = MN²
MN = √16a²
MN = 4a
Therefore, vertices of the triangle will be L(0, 0), M(3a, 0) and N(0, 4a).
Option (2) will be the answer.
Usually you are given more information about the rectangle such as distance of length in terms of width.
You know that the formula for perimeter is
P=2(l+w)
Substitute p and the other values to find width.
Hope I helped :)
Multiply the first equation by 2 to then use elimination by adding the 2 equations.
So, 14x-2y=14
+. x+2y=6
Equals 15x=20 so x=20/15=4/3
Plug in to first equation to get y
7(4/3)-y=7
28/3-y=7
28/3-y=21/3
So y=7/3
Plug both x and y into second equation to check
4/3+2(7/3)=
4/3+14/3=18/3=6 it works
So x=4/3, y=7/3
Hope this helps! Have a blessed day!
Answer:
B
Step-by-step explanation:
Hope this helps! have a great day!
