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dexar [7]
3 years ago
12

Select "Yes" or "No" to indicate whether the ordered pair is on the graph of the function f(x)=−25^x+1.

Mathematics
2 answers:
Verdich [7]3 years ago
5 0

Hello! Just took the test:

(1,625) No

(0,-25) Yes

(-1,-1) Yes

KengaRu [80]3 years ago
3 0
<span>(1,625) No (0,-25) No (-1,-1) No Think about what an integer exponent means for an negative base and you'll understand this problem. For instance the powers of -25 would be -25^1 = -25 -25^2 = (-25) * (-25) = 625 -25^3 = (-25)*(-25)*(-25) = -15625 and so on, giving 390625, -9765625, 244140625, etc. But that's a different subject. For the ordered pairs given, let's check them out. (1,625) -25^1 + 1 = -25 + 1 = -24. And -24 is not equal to 625, so "No". (0,-25) -25^0 + 1 = 1 +1 = 2. Note: Any real number other than 0 raised to the 0th power is 1. And 2 is not equal to -25, so "No". (-1,-1) -25^(-1) + 1 = 1/(-25^1) + 1 = 1/-25 + 1 = 24/25. And 24/25 is not equal to -1, so also "No".</span>
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3 years ago
The angle of elevation to the top of a water tower from point A on the ground is 19.9°. From point B, 50.0 feet closer to the to
zepelin [54]

Answer:

Answer in terms of a trigonometric function :

h = \frac{20tan(19.9)}{0.4-tan(19.9)}

Answer in figures

h = 190.5 feet

Step-by-step explanation:

Consider the sketch attached below to better understand the problem.

Let x be the distance between point B and the base of the water tower.

tan (19.9)=\frac{h}{50+x} ---------------equation 1\\

tan (21.8)=\frac{h}{x}----------------equation 2

From equation 2,

x =\frac{h}{tan21.8}=\frac{h}{0.4}

substituting the value of x into equation 1, we get

tan (19.9)=\frac{h}{50+(\frac{h}{0.4} )}

tan 19.9=h\times \frac{0.4}{20+h}

cross multiplying,

20\times tan(19.9) +htan(19.9)=0.4h

20tan(19.9)= h(0.4-tan(19.9))

h= \frac{20tan (19.9)}{0.4-tan (19.9)}

The height of the tower is h= \frac{20tan (19.9)}{0.4-tan (19.9)} in terms of the trig function "Tan"

The equation can simply be evaluated to get the answer in figures since the angles are given in the question

5 0
3 years ago
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