Question

(1 point) Write the given second order equation as its equivalent system of first order equations. u′′+6.5u′−1.5u=8sin(3t),u(1)=−3,u′(1)=−1.5 Use v to represent the "velocity function", i.e. v=u′(t). Use u and v for the two functions, rather than u(t) and v(t). (The latter confuses webwork. Functions like sin(t) are OK.)

Answer 1

Answer:

$v' + 6.5\cdot v = 1.5\cdot u + 8\cdot \sin 3t$

Step-by-step explanation:

The differential equation is:

$v' + 6.5 \cdot v -1.5\cdot u = 8 \cdot \sin 3t$

$v' + 6.5\cdot v = 1.5\cdot u + 8\cdot \sin 3t$