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Gekata [30.6K]
3 years ago
6

(1 point) Write the given second order equation as its equivalent system of first order equations. u′′+6.5u′−1.5u=8sin(3t),u(1)=

−3,u′(1)=−1.5 Use v to represent the "velocity function", i.e. v=u′(t). Use u and v for the two functions, rather than u(t) and v(t). (The latter confuses webwork. Functions like sin(t) are OK.)
Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

v' + 6.5\cdot v = 1.5\cdot u + 8\cdot \sin 3t

Step-by-step explanation:

The differential equation is:

v' + 6.5 \cdot v -1.5\cdot u = 8 \cdot \sin 3t

v' + 6.5\cdot v = 1.5\cdot u + 8\cdot \sin 3t

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Margaret [11]

Answer:

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7 0
3 years ago
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KengaRu [80]
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3 0
3 years ago
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Answer:

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Step-by-step explanation:

4 0
2 years ago
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Find the product.<br> (3n - 1)(7n-7)
slega [8]

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21n² - 28n + 7

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6 0
3 years ago
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Murljashka [212]

Answer:

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7 0
3 years ago
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