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Gekata [30.6K]
3 years ago
6

(1 point) Write the given second order equation as its equivalent system of first order equations. u′′+6.5u′−1.5u=8sin(3t),u(1)=

−3,u′(1)=−1.5 Use v to represent the "velocity function", i.e. v=u′(t). Use u and v for the two functions, rather than u(t) and v(t). (The latter confuses webwork. Functions like sin(t) are OK.)
Mathematics
1 answer:
Over [174]3 years ago
6 0

Answer:

v' + 6.5\cdot v = 1.5\cdot u + 8\cdot \sin 3t

Step-by-step explanation:

The differential equation is:

v' + 6.5 \cdot v -1.5\cdot u = 8 \cdot \sin 3t

v' + 6.5\cdot v = 1.5\cdot u + 8\cdot \sin 3t

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Use the Angle Addition Postulate to find the measure of each angle.
Simora [160]
For number 15 and 16, you just have to find the absolute difference between the two points along the calibration of the protractor.

15. ∠BXC = |B - C| = |140° - 110°| = 30°
16. ∠BXE = |B - E| = |140° - 30°| = 110°

For numbers 20 and 21, apply the Angle Addition Postulate. This is when you add the individual interior angles to equate to the total angle.

20. ∠PQS = ∠PQR + ∠RQS
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5 0
3 years ago
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lesantik [10]

Answer:

Step-by-step explanation:

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3 years ago
Which number is prime... 11. 49. 51. 81
Rzqust [24]
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8 0
3 years ago
Solve for (f+g)(5) if f(x)=6x+3 and g(x)=x-4 show you work please
Diano4ka-milaya [45]
There are two ways to do this.

The first way is to algebraically find (f+g)(x) first and plug in x = 5 later. Doing that method leads us to
(f+g)(x) = f(x) + g(x)
(f+g)(x) = 6x+3 + x-4
(f+g)(x) = 7x-1
(f+g)(5) = 7(5)-1
(f+g)(5) = 34

OR

you can compute f(5) and g(5) first, then add up those sub-results to get
f(x) = 6x+3
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f(5) = 33
g(x) = x-4
g(5) = 5-4
g(5) = 1
Adding up these results gives: (f+g)(5) = f(5) + g(5) = 33+1 = 34

Either way, the final answer is 34

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yKpoI14uk [10]

Answer:

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