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3 years ago

Helppp pleaseeeee!!!!!!!

Mathematics

1 answer:

AleksandrR [38]3 years ago

7 0

I’m pretty sure all you have to do is plug in your numbers for example number 5 is y=2x-2 so you would plug in the first number which is -1. So the equation that you solve would be y=2 times -1 minus 2. That would be -4. I hope this helps. If you need further explanation please say so in comments.

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1/4y =6

kondaur [170]

Answer: Y=24

Step-by-step explanation:1/4 y=6

*4 *4

y= 24

Math really is a universal language, Buenos noches amigo.

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3 years ago

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Colt1911 [192]

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2 years ago

Write the following expression as a simplified polynomial in standard form.

LiRa [457]

Answer:

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3 years ago

Find the domain of the function f(x)=<img src="https://tex.z-dn.net/?f=%5Csqrt%7Bx%5E3-16x%7D" id="TexFormula1" title="\sqrt{x^3

Anon25 [30]

Answer:

Please check the explanation.

Step-by-step explanation:

Given the function

$f\left(x\right)=\sqrt{x^3-16x}$

We know that the domain of the function is the set of input or arguments for which the function is real and defined.

In other words,

Domain refers to all the possible sets of input values on the x-axis.

Now, determine non-negative values for radicals so that we can sort out the domain values for which the function can be defined.

$x^3-16x\ge 0$

as x³ - 16x ≥ 0

$\left(x+4\right)\left(x-4\right)\ge \:0$

Thus, identifying the intervals:

$-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4$

Thus,

The domain of the function f(x) is:

$x\left(x+4\right)\left(x-4\right)\ge \:0\quad :\quad \begin{bmatrix}\mathrm{Solution:}\:&\:-4\le \:x\le \:0\quad \mathrm{or}\quad \:x\ge \:4\:\\ \:\mathrm{Interval\:Notation:}&\:\left[-4,\:0\right]\cup \:[4,\:\infty \:)\end{bmatrix}$

And the Least Value of the domain is -4.

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3 years ago

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sammy [17]

Answer:

Tell whether the following equations represent a linear function.

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−x² + 3y = 19--quadratic equation

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3 years ago