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Ivan
3 years ago
5

When HCl(g) reacts with O2(g) to form H2O(g) and Cl2(g), 6.84 kcal of energy are evolved for each mole of HCl(g) that reacts. Wr

ite a balanced equation for the reaction with an energy term in kcal as part of the equation. Use the SMALLEST INTEGER coefficients possible and put the energy term in an appropriate box. If a box is not needed, leave it blank.
Chemistry
1 answer:
puteri [66]3 years ago
6 0

Answer:

4HCl(g)+O2(g)= 2H2O(g)+2Cl2(g)

∆H=-27.36 kcal

Explanation:

The balanced equation shows that four molecules of HCl reacts with one molecule of Oxygen to give two molecules of water and two molecules of chlorine gas and evolves energy in a combustion reaction.

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The piece of metal is magnetic
Alex_Xolod [135]

Answer:

Explanation:

Magnetic materials are always made of metal, but not all metals are magnetic. Iron is magnetic, so any metal with iron in it will be attracted to a magnet. Steel contains iron, so a steel paperclip will be attracted to a magnet too. Most other metals, for example aluminium, copper and gold, are NOT magnetic.

5 0
3 years ago
As a part of a clinical study, a pharmacist is asked to prepare a modification of a standard 22g package of a 2% mupirocin ointm
Vesna [10]

Answer:

226.8 mg of mupirocin powder are required

Explanation:

Given that;

weight of standard pack = 22 g

mupirocin by weight = 2%

so weight of mupirocin = 2% × 22 = 2/100 × 22 = 0.44 g

so by adding the needed quantity of mupirocin powder to prepare a 3% w/w mupirocin ointment

mg of mupirocin powder are required = ?, lets rep this with x

Total weight of ointment = 22 + x g

Amount of mupirocin  = 0.44 + x g

percentage of mupirocin  in ointment is 3?

so

3/100 = 0.44 + x g / 22 + x g

3( 22 + x g ) = 100( 0.44 + x g )

66 + 3x g = 44 + 100x g

66 - 44 = 100x g - 3x g

97 x g = 22

x g = 22 / 97

x g = 0.2268 g

we know that; 1 gram = 1000 Milligram

so 0.2268 g = x mg

x mg = 0.2268 × 1000

x mg  = 226.8 mg

Therefore, 226.8 mg of mupirocin powder are required

8 0
3 years ago
Why the standard enthalpy change of hydration of copper sulphate cannot be measured directly ?
Juliette [100K]

It is difficult to measure the enthalpy change of hydration accurately in a direct way because the hydration process can't be controlled directly. Instead, anhydrous and hydrated copper(II) sulfate can be dissolved in water. Each 'route' produces a solution of hydrated copper(II) sulfate.

5 0
3 years ago
How many half-lives have passed if the amount of Parent Isotope is 12.5%?
OverLord2011 [107]

Answer:

Three half lives.

Explanation:

Given data:

Number of half lives passed = ?

Amount of parent isotope left = 12.5%

Solution:

At time zero = 100%

At 1st half life = 100%/2 = 50%

At second half life = 50%/2 = 25%

At third half life = 25%/2 = 12.5%

It means three half lives would passed.

7 0
3 years ago
Complete the lewis structures of the atoms and ions by adding electrons, as needed.
Lana71 [14]
Hope this helps! Na+ lost an electron, so I just left a "+" symbol to show that, and fluorine gained an electron, hence the "-" symbol.

3 0
4 years ago
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