The outer layers are the photosphere the chromosphere the transition region in the corona
The moles of CaCO3 which are there in antacid tablet that contain 0.515g CaCO3 is calculated as follows
moles =mass/molar mass
the molar mass of CaCO3 = ( 40 x1)+ (12 x 1) + (16 x 3)= 100 g/mol
moles is therefore= 0.515g/100 g/mol= 5.15 x10^-3 moles
Answer is: 22,4 l of nitrogen.
Chemical reaction: 3H₂ + N₂ ⇄ 2NH₃.
V(NH₃) = 44,8 l = 44,8 dm³.
V(N₂) = ?
n(NH₃) = V(NH₃) ÷ Vm
n(NH₃) = 44,8 dm³ ÷ 22,4 dm³/mol
n(NH₃) = 2 mol.
from reaction: n(N₂) : n(NH₃) = 1 : 2
n(N₂) : 2 mol = 1 : 2
n(N₂) = 1 mol.
V(N₂) = n(N₂) · Vm
V(N₂) = 1 mol · 22,4 dm³/mol = 22,4 dm³.
Vm - molar volume
