Answer:
Six C atoms (C₆); five H atoms (H₅); one N atom (N); no O atoms
Explanation:
The rule of 13 states that the formula of a compound is a multiple n of 13 (the molar mass of CH) plus a remainder r.
MF = CₙHₙ₊ᵣ
Y has a molecular mass of 91 u
91/13 =7r0
The formula can't be C₇H₇ because a hydrocarbon must have an even number of H atoms,
The odd mass and the odd number of H atoms make it reasonable to add an N atom and subtract CH₂ (CH₂ = 14):
C₇H₇ + N - CH₂ = C₆H₅N
Check:
6C = 6 × 12.000 = 72.000 u
5H = 5 × 1.008 = 5.040
1N = 1 × 14.003 = <u>14.003 </u>
TOTAL = 91.043 u
This is excellent agreement with the observed mass of 91.0425 u.
There are six C atoms (C₆)
There are five H atoms (H₅)
There is one N atom (N)
There are no O atoms.
The SAME number of molecules are in ANY “mole” of a compound or element. So, you only need to ... 24 g116 g/mol=0.207 moles of FeF3.
Hello!
the atomic mass of one atom of hydrogen is equal to 1.00784 in atomic mass units
one atomic mass unit is equal to 3.6609e-27 pounds
which means one atom of hydrogen is equal to 3.9478732e-27 pounds
I hope this helps, and have a nice day!
Answer: In the three-dimensional structure of methane, CH₄, the hydrogen atoms attached to a carbon atom are aligned <span>
<u>at the corners of a Tetrahedron</u>.
Explanation: In
Methane (CH</span>₄) the central atom (carbon) is bonded to four hydrogen atoms. So, the central atom is having four electron pairs and all pairs are bonding pairs and lacks any lone pair of electron. According to
Valence Shell Electron Pair Repulsion (VSEPR) Theory the central atom with
four bonding pair electrons and
zero lone pair electrons will attain a
tetrahedral geometry with
bond angles of 109°. Hence, the shape of CH₄ is tetrahedral.