How many eighty fours are in 672?
672 ÷ 84 = 8
8 eighty fours are in 672.
Answer:100
Step-by-step explanation:
52+28=80
180-80=100
Answer:
8 hours
Step-by-step explanation:
Its is on the chart and is at the top
There are the combinations that result in a total less than 7 and at least one die showing a 3:
[3, 3] [3,2] [2,1] [1,3] [2,3]
The probability of each of these is 1/6 * 1/6 = 1/36
There is a little ambiguity here about whether or not we should count [3,3] as the problem says "and one die shows a 3." Does this mean that only one die shows a 3 or at least one die shows a 3? Assuming the latter, the total probability is the sum of the individual probabilities:
1/36 + 1/36 + 1/36 + 1/36 + 1/36 = 5/36
Therefore, the required probability is: 5/36