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RoseWind [281]
3 years ago
12

How can using properties help you to simplify expressions?

Mathematics
1 answer:
alina1380 [7]3 years ago
4 0
Well,properties can help you because you can shorten or make an equation more understandable, like using distributive property in the example 2(5x-3), you can rewrite it as 10x-6. See?
You might be interested in
Find an equation in rectangular coordinates for the cylindrical equation r = 2sintheta
frutty [35]

Answer:

x^2+(y-1)^2=1

Step-by-step explanation:

The given cylindrical equation is

r=2\sin \theta

Multiply both sides by r.

r^2=2r\sin \theta           .... (1)

The required formulas are

x=r\cos \theta,y=r\sin \theta,r^2=x^2+y^2

Substitute r\sin \theta =y,r^2=x^2+y^2 in equation (1).

x^2+y^2=2y

x^2+y^2-2y=0

Add 1 on both sides.

x^2+(y^2-2y+1)=1

(x-0)^2+(y-1)^2=1^2                    [\because (a-b)^2=a^2-2ab+b^2]

It is the equation of a circle centered at (0,1) with radius 1.

Therefore, the equation in rectangular coordinates is x^2+(y-1)^2=1.

3 0
3 years ago
Mr. jovanovski is having wood flooring put in his rectangular living room. the area of the room is 234 square feet. the length o
OlgaM077 [116]
By definition the area of a rectangle is:
 A = l * w
 Where,
 l: long
 w: width
 So we have to clear the width:
 w = A / l
 Substituting the values:
 w = (234) / (18) = 13
 w = 13 feets
 answer
 the width, in feet, of the room is 13
5 0
3 years ago
Read 2 more answers
A study of class attendance and grades among first-year students at a state university showed that, in general, students who mis
ratelena [41]

Answer:

the numerical value of the correlation between percent of classes attended and grade index is r = 0.4

Step-by-step explanation:

Given the data in the question;

we know that;

the coefficient of determination is r²

while the correlation coefficient is defined as r = √(r²)

The coefficient of determination tells us the percentage of the variation in y by the corresponding variation in x.

Now, given that class attendance explained 16% of the variation in grade index among the students.

so

coefficient of determination is r² = 16%

The correlation coefficient between percent of classes attended and grade index will be;

r = √(r²)

r = √( 16% )

r = √( 0.16 )

r = 0.4  

Therefore,  the numerical value of the correlation between percent of classes attended and grade index is r = 0.4

3 0
3 years ago
For each of the following functions, determine if they are injective. Also determine if theyare surjective. Also determine if th
timurjin [86]

Answer:

Check below

Step-by-step explanation:

1. Definition for intervals

(a,b)=\left \{ x\in\Re : a

2. Functions

1) \Re \rightarrow \Re \\ f(x)=x

Let's perform graph tests.

That's an one to one, injective function. Look how any horizontal line touches that only once. Also, It's a surjective and a bijective one.

2)\Re\geq0\rightarrow\Re , f(x)=x+1\\

Injective, surjective and bijective.

Injective: a horizontal line crosses the graph in one point.

3)f:\Re\geq 0\rightarrow\Re, f(x) = cos(x)

The cosine function is not injective, bijective nor surjective.

4)f:\Re\rightarrow\Re \:f(x)=ex

Since e, is euler number it's a constant. It's also injective, surjective and bijective.

5)  Quite unclear format

6) \:f:\Re\rightarrow(0,\infty), f(x) =ex

Despite the Restriction for the CoDomain, the function remains injective, surjective and therefore bijective.

7) f:\Re\geq 0 \rightarrow  \Re\geq0, f(x) =x^{4}

Not injective nor surjective therefore not bijective too.

8).f:\{-1,2,-3\}}\rightarrow \{1,4,9\}, f(x) =x^{2}

f(-1)=1, f(2)=4, f(-3)=9

Injective (one to one), Surjective,  and Bijective.

10) f:\Re\geq 0\rightarrow [-1,1], f(x)= cos(x)\\-1=cos(x) \therefore x=\pi,3\pi,5\pi,etc.

Surjective.

11.f:R\geq 0[-1,1], f(x) = 0\\

Surjective

12.f: US Citizens→Z, f(x) = the SSN of x.

General function

13.f: US Zip Codes→US States, f(x) = The state that x belongs to.

Surjective

7 0
2 years ago
HELPPPPPPPPPPP
True [87]

Answer:

Part A

  • C. 7.25

Part B

  • B. Ryan Shafer has been more consistent because his mean absolute deviation is less than Norm Duke’s.

Step-by-step explanation:

<u>Given data:</u>

  • 299, 281, 285, 269, 280, 269, 286, 287
<h3>Part A</h3>

<u>Find the mean of the data above:</u>

  • (299 + 281 + 285 + 269 + 280 + 269 + 286 + 287)/8 = 282

<u>Find absolute deviations, an absolute value of the difference of data and the mean:</u>

  • 299 - 282 = 17 ⇒ 17
  • 281 - 282 = -1 ⇒ 1
  • 285 - 282 = 3 ⇒ 3
  • 269 - 282 = -13 ⇒ 13
  • 280 - 282 = 2 ⇒ 2
  • 269 - 282 = -13 ⇒ 13
  • 286 - 282 = 4 ⇒ 4
  • 287 - 282 = 5  ⇒ 5

<u>Find mean absolute deviation:</u>

  • (17 + 1 + 3 + 13 + 2 + 13 + 4 + 5)/8 = 7.25

Correct choice is C

<h3>Part B</h3>

Less mean absolute deviation is the sign of more consistent data.

Since Ryan Shafer has smaller mean absolute deviation, he has been more consistent 7 < 7.25

Correct choice is B.

5 0
3 years ago
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