The average value is given by

Setting

, you get

, and the integral becomes


Given:
A square base pyramid whose base length is 10 in. and height of triangular surface is 4 in.
To find:
The surface area of the pyramid to the nearest whole number.
Solution:
A square base pyramid contains square base with edge 10 in. and 4 congruent triangles with base 10 in. and height 4 in.
Area of a square is



So, area of square base is 100 sq. in.
Area of a triangle is



So, area of each triangular surface is 20 sq. in.
Now, the total surface area of the pyramid is
Total area = Area of square base + Area of 4 congruent triangles.




Therefore, the area of the pyramid is 180 sq. in.
I know for m<5 is 28 and m<6= 62, because 90-28 = 62
Answer:
y=1/6x -1
Step-by-step explanation:
Use point-slope form to convert it to y=mx+b.
y-y1=m(x-x1)
y+2=1/6(x+6)
Distribute and simplify.
y+2=1/6x+1
y=1/6x-1