Consider this option:
1. if the point (4;6) is the centre of the circle and the point (2;5) is the first endpoint of its diameter, then point (4;6) is the middle point of the diameter (it means that is the middle between the 1st and the 2d endpoints of diameter).
2. using the property described above:
for x of the 2d endpoint of the diameter: x=4*2-2=6;
for y of the 2d endpoint of the diameter: y=6*2-5=7.
answer: (6;7)
The triangles are congruent by SAS, so the two angles with 7x and 3x+16 are equal. So
7x=3x+16
4x=16
x=4
So KJL=7(4)=28.
Answer:
3.5
Step-by-step explanation:
