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3 years ago

Which inequalities are true? Check all that apply

Mathematics

2 answers:

wel3 years ago

5 0

Answer:

A,B,C,E

Step-by-step explanation:

leva [86]3 years ago

3 0

Answer:

A , B, C, E

Step-by-step explanation:

√4 = 2

√5 = 2.24

√5.5 = 2.36

√6 = 2.45

√8 = 2.83

√9 = 3

√5 < 2.3<√6

2.24 < 2.3 < 2.45 True

√5 < 2.4<√6

2.24 < 2.4 < 2.45 True

√4 < √5 < √5.5

2 < 2.24 < 2.36 True

√8 < 3 < √9

2.83 < 3 < 3 False

√8 < 2.9 < √9

2.83 < 2.9 < 3 True

√4 < 4.5 < √5

2 < 4.5 < 2.24 False

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a group consisted of 2 girls for every boy. 24 girls joined the group. there are now 5 girls for every boy. how many boys are in

mixer [17]

The new ratio is 5:1.
5 girls to every 1 boy is, 8 boys and 40 girls.
So there is now 8 boys in the group

7 0

3 years ago

Read 2 more answers

Let p0, p1, and p2 be the orthogonal polynomials described below, where the inner product on P4 is given by evaluation at -2, -1

Mamont248 [21]

Answer:

$\frac{51}{5}t$

Step-by-step explanation:

Let W = $(p_0, p_1, p_2)$ be orthogonal polynomials which is equal to $(4, 3t, t^2 -2)$ , which defines the inner products as

$(f,g)=f(-2)g(-2)+f(-1)g(-1)+f(0)g(0)+f(1)g(1)+f(2)g(2)$

Now, we find the orthogonal projection of $p=3t^3$ on W.

So the projection is

$Proj_W p = \frac{(p_0,p)}{(p_0,p_0)}p_0+\frac{(p_1,p)}{(p_1,p_1)}p_1+\frac{(p_2,p)}{(p_2,p_2)}p_2$

$(p_0,p)=p_0(-2)p(-2)+p_0(-1)p(-1)+p_0(0)p(0)+p_0(1)p(1)+p_0(2)p(2)$

$=4(-24)+4(-3)+4(0)+4(3)+4(24)=0$

$(p_0,p_0)=p_0(-2)p_0(-2)+p_0(-1)p_0(-1)+p_0(0)p_0(0)+p_0(1)p_0(1)+p_0(2)p_0(2)$

$=4(4)+4(4)+4(4)+4(4)+4(4)=80$

$(p_1,p)=p_1(-2)p(-2)+p_1(-1)p(-1)+p_1(0)p(0)+p_1(1)p(1)+p_1(2)p(2)$

$=(-6)(-24)+(-3)(-3)+0(0)+3(3)+6(24)=306$

$(p_1,p_1)=p_1(-2)p_1(-2)+p_1(-1)p_1(-1)+p_1(0)p_1(0)+p_1(1)p_1(1)+p_1(2)p_1(2)$

$=(-6)(-6)+(-3)(-3)+0(0)+3(3)+6(6)=90$

$(p_2,p)=p_2(-2)p(-2)+p_2(-1)p(-1)+p_2(0)p(0)+p_2(1)p(1)+p_2(2)p(2)$

$=2(-24)+(-1)(-3)+(-2)(0)+(-1)(3)+2(24)=0$

$(p_2,p_2)=p_2(-2)p_2(-2)+p_2(-1)p_2(-1)+p_2(0)p_2(0)+p_2(1)p_2(1)+p_2(2)p_2(2)$

$=(2)(2)+(-1)(-1)+(-2)(-2)+(-1)(-1)+2(2)=14$

Therefore,

$Proj_W p = \frac{(p_0,p)}{(p_0,p_0)}p_0+\frac{(p_1,p)}{(p_1,p_1)}p_1+\frac{(p_2,p)}{(p_2,p_2)}p_2$

$=\frac{0}{80}(4)+\frac{306}{90}(3t)+\frac{0}{14}(t^2-2)$

$=\frac{51}{5}t$

6 0

3 years ago

With the sun at an angle of 30 degrees to the ground, a tree casts an 80 ft shadow. how tall is the tree?

Sholpan [36]

Let tree's height = h

h/80 = tan 30
⇒ h = 80 tan 30
⇒ h = 80 * 1/√3
⇒ h = 46.19 ft

8 0

3 years ago

What is tan(x)-5=0<br> (With steps)

sp2606 [1]

Tanx-5=0
tanx=5
tan inverse (5)=x
78.69

7 0

3 years ago

laws of Sines with find the angle. Find each measurement indicated. Round your answers to the nearest tenth. Part 4

lukranit [14]

Answer:

10. Not enough information

11. B ≈ 12.0°

12. A ≈ 34.1°

Step-by-step explanation:

10. Not enough information

11.

We need to use the Law of Sines, which states that for a triangle with lengths a, b, and c and angles A, B, and C:

$\frac{a}{sinA} =\frac{b}{sinB} =\frac{c}{sinC}$

Here, we can say that AB = c = 38, C = 128, and AC = b = 10. Plug these in to find B:

$\frac{b}{sinB} =\frac{c}{sinC}$

$\frac{10}{sinB} =\frac{38}{sin128}$

Solve for B:

B ≈ 12.0°

12.

Use the Law of Sines as above.

$\frac{a}{sinA} =\frac{b}{sinB}$

$\frac{23}{sinA} =\frac{28}{sin(43)}$

Solve for A:

A ≈ 34.1°

6 0

3 years ago