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aliina [53]
4 years ago
13

Give the convex pentagon, what are the values for x and y?

Mathematics
1 answer:
Dima020 [189]4 years ago
4 0
Now.. if you check the picture below

notice that, "x" and "y" are just "supplementary" angles

so.. what the dickens is "x" anyway?

well, "x" is an internal angle to the pentagon

and \bf \textit{sum of all interior angles in a polygon}\\\\
180(n-2)\qquad 
n=\textit{number of sides}

so.. this polygon is a pentagon, or PENTA=5, 5 sides
so all internal angles add up to 180(5-2) or 180*3 = 540

now, check the angle on the bottom-left-corner, is a right-angle

so... you already have 4 angles given inside

so   x + 80 + 160 + 100 + 90 = 540

solve for "x"

what about "y"?   well, y = 180 - x

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Vilka [71]
12.5 * .25=3 1/8 miles running part  
3.125 * .5=1 9/16 miles kayaking part
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8 0
3 years ago
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What is the area of the circle? With a 5cm radius.
larisa [96]
Hi there!

The formula for the area of a circle is A = pi x r^2. Using this formula, we can plug in the radius and solve for the area.

WORK:
A = pi x (5)^2
A = pi x 25
A = 25pi cm^2

ANSWER:
B - 25pi cm^2

Hope this helps!! :)
If there's anything else that I can help you with, please let me know!
7 0
3 years ago
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The table shows a function. Is the function linear or nonlinear?
Firdavs [7]

Answer:

nonlinear

Step-by-step explanation:

7 0
3 years ago
What is 2 (log Subscript 3 Baseline 8 + log Subscript 3 Baseline z) minus log Subscript 3 Baseline (3 Superscript 4 Baseline min
Ilya [14]

Answer:

Value of expression in single logarithm is \log_3\left(2z^2\right).

Step-by-step explanation:

Given expression is,

2\left(\log_3\left(8\right)+\log_3\left(z\right)\right)-\log_3\left(3^4-7^2\right)

Now using logarithmic rule to solve the expression as follows,

Applying product rule of logarithmic,

\log_c\left(a\right)+\log_c\left(b\right)=\log_c\left(ab\right)

Therefore,

2\log_3\left(8z\right)-\log_3\left(3^4-7^2\right)

Applying power rule of logarithmic,

a\log_c\left(b\right)=\log_c\left(b^a\right)

Therefore,

\log_3\left(\left(8z\right)^2\right)-\log_3\left(3^4-7^2\right)

\log_3\left(\left(64z^2\right)\right)-\log_3\left(3^4-7^2\right)

Applying quotient rule of logarithmic,

\log_c\left(a\right)-\log_c\left(b\right)=\log_c\left(\frac{a}{b}\right)

Therefore,

\log_3\left(\dfrac{\left(64z^2\right)^2}{3^4-7^2}\right)

Simplifying,

\log_3\left(\dfrac{\left(64z^2\right)^2}{81-49}\right)

\log_3\left(\dfrac{\left(64z^2\right)^2}{32}\right)

\log_3\left(2z^2\right)

Therefore value of expression is \log_3\left(2z^2\right)

6 0
4 years ago
Read 2 more answers
Is the answer e? I think it is
ioda

Answer: I am pretty sure you are correct from my standpoint

Step-by-step explanation:

If you look closely he is pretty close to the answer or it is the answer or this is just answer on my point or if its wrong try b

6 0
2 years ago
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