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algol [13]
2 years ago
11

Simplify completely quantity 4 x squared minus 32 x plus 48 all over quantity 3 x squared minus 17 x minus 6. (1 point)

Mathematics
1 answer:
Galina-37 [17]2 years ago
8 0

Given rational expression is:


\frac{(4x^2-32x+48)}{(3x^2-17x-6)}

Now we can simplify this by factoring as shown below:


=\frac{4(x^2-8x+12)}{(3x^2-17x-6)}


=\frac{4(x-2)\left(x-6\right)}{(3x^2-18x+1x-6)}


=\frac{4(x-2)\left(x-6\right)}{3x\left(x-6\right)+1\left(x-6\right)}


=\frac{4(x-2)\left(x-6\right)}{(3x+1)\left(x-6\right)}


=\frac{4(x-2)}{(3x+1)}



Hence final answer is \frac{4(x-2)}{(3x+1)}




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Answer:

(x - 1)²/4² - (y - 2)²/2² = 1 ⇒ The bold labels are the choices

Step-by-step explanation:

* Lets explain how to solve this problem

- The equation of the hyperbola is x² - 4y² - 2x + 16y - 31 = 0

- The standard form of the equation of hyperbola is

  (x - h)²/a² - (y - k)²/b² = 1 where a > b

- So lets collect x in a bracket and make it a completing square and

  also collect y in a bracket and make it a completing square

∵ x² - 4y² - 2x + 16y - 31 = 0

∴ (x² - 2x) + (-4y² + 16y) - 31 = 0

- Take from the second bracket -4 as a common factor

∴ (x² - 2x) + -4(y² - 4y) - 31 = 0

∴ (x² - 2x) - 4(y² - 4y) - 31 = 0

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∵ √x² = x

∴ The 1st term in the bracket is x

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∵ √y² = y

∴ The 1st term in the bracket is x

∵ 4y ÷ 2 = 2y

∴ The product of the 1st term and the 2nd term is 2y

∵ The 1st term is y

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∴ The bracket is 4(y - 2)²

∵ 4(y - 2)² = 4(y² - 4y + 4)

∴ To complete the square add 4 to the bracket and subtract 4 out

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∴ 4[y² - 4y + 4) - 4]

- Lets put the equation after making the completing square

∴ (x - 1)² - 1 - 4[(y - 2)² - 4] - 31 = 0 ⇒ simplify

∴ (x - 1)² - 1 - 4(y - 2)² + 16 - 31 = 0 ⇒ add the numerical terms

∴ (x - 1)² - 4(y - 2)² - 16 = 0 ⇒ add 14 to both sides

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∴ (x - 1)²/16 - (y - 2)²/4 = 1

∵ 16 = (4)² and 4 = (2)²

∴ The standard form of the equation of the hyperbola is

   (x - 1)²/4² - (y - 2)²/2² = 1

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