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algol [13]
3 years ago
11

Simplify completely quantity 4 x squared minus 32 x plus 48 all over quantity 3 x squared minus 17 x minus 6. (1 point)

Mathematics
1 answer:
Galina-37 [17]3 years ago
8 0

Given rational expression is:


\frac{(4x^2-32x+48)}{(3x^2-17x-6)}

Now we can simplify this by factoring as shown below:


=\frac{4(x^2-8x+12)}{(3x^2-17x-6)}


=\frac{4(x-2)\left(x-6\right)}{(3x^2-18x+1x-6)}


=\frac{4(x-2)\left(x-6\right)}{3x\left(x-6\right)+1\left(x-6\right)}


=\frac{4(x-2)\left(x-6\right)}{(3x+1)\left(x-6\right)}


=\frac{4(x-2)}{(3x+1)}



Hence final answer is \frac{4(x-2)}{(3x+1)}




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Step-by-step explanation:

1st term: 2(1) - 1

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2 years ago
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$6750 in the bank account and $20,250 in the stock fund

Step-by-step explanation:

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1. |4n-15|=|n|<br> 2. |2c+8|=|10c| <br> can you please show the work for both
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Problem 1

<h3>Answers: n = 3 or n = 5</h3>

---------------

Work Shown:

|4n - 15| = |n|\\\\4n - 15 = n \ \text{ or } \ 4n-15 = -n\\\\-15 = n-4n \ \text{ or } \ -15 = -n-4n\\\\-15 = -3n \ \text{ or } \ -15 = -5n\\\\-3n = -15 \ \text{ or } \ -5n = -15\\\\n = \frac{-15}{-3} \ \text{ or } \ n = \frac{-15}{-5}\\\\n = 5 \ \text{ or } \ n = 3\\\\

==============================================

Problem 2

<h3>Answers: c = 1 or c = -2/3</h3>

-----------------------

Work Shown:

|2c+8| = |10c|\\\\2c+8 = 10c \ \text{ or } \ 2c+8 = -10c\\\\8 = 10c-2c \ \text{ or } \ 8 = -10c-2c\\\\8 = 8c \ \text{ or } \ 8 = -12c\\\\8c = 8 \ \text{ or } \ -12c = 8\\\\c = \frac{8}{8} \ \text{ or } \ c = \frac{8}{-12}\\\\c = 1 \ \text{ or } \ c = -\frac{2}{3}

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