The right answer is "2"
the divisiveness rule says that the number which it's last two digit is divisible to 4 and 2 is divisible to 8 so if you add another digit you have to make it divisible to 4 and 2 which in this case is number "2"
Answer:
No real roots
Step-by-step explanation:
Given
7x² + 5x + 1 = 0 ← in standard form
with a = 7, b = 5, c = 1
To determine the nature of the roots use the discriminant
Δ = b² - 4ac
• If b² - 4ac > 0 then roots are real and distinct
• If b² - 4ac = 0 then roots are real and equal
• If b² - 4ac < 0 then the roots are not real
Here
b² - 4ac = 5² - (4 × 7 × 1) = 25 - 28 = - 3
Thus the 2 roots are not real
what do you need help with
Step-by-step explanation:
Erase the dot points you already have. We are supposed to substitute those values in the right side of problem 1 into the function as x.
For example if x=-4
If x=-2
If x=0
So our point should be
-4,9
-2,7
0,5
-2,3
-4,1.
The range is all possible y values in a function. Since this is discrete and we are given the domain, our range will just be the y value of the points you graphed.
(9,7,5,3,1)
