Answer:
24.75m ≤ 30m < 35.75m
Step-by-step explanation:
Minimum area:
5.5 (lower bound of 6m) * 4.5 (lower bound of 5m) = 24.75m
Maximum area:
6.5 (upper bound of 6m) * 5.5 (upper bound of 5m) = 35.75m
Normal area:
6*5=30m
I hope that makes some sense or helps a little!
How do we graph anything? Make a table of values for x and y and then plot each point. After plotting each point on the xy-plane, connect each point with a straight line or curve (depending on the function).
In this case, we must first isolate y.
y = (-4/3)x + 8y
y - 8y = (-4/3)x
-7y = (-4/3)x
y = (-4/3)x ÷ (-7)
y = (4/21)x
Now follow the steps above.
Answer:
2/3 = 1.5
Step-by-step explanation:
Answer:
2nd and 4th on edg
Step-by-step explanation:
3+21pi / 2 +4
3-21pi / 2 -4
<span>The maxima of a differential equation can be obtained by
getting the 1st derivate dx/dy and equating it to 0.</span>
<span>Given the equation h = - 2 t^2 + 12 t , taking the 1st derivative
result in:</span>
dh = - 4 t dt + 12 dt
<span>dh / dt = 0 = - 4 t + 12 calculating
for t:</span>
t = -12 / - 4
t = 3
s
Therefore the maximum height obtained is calculated by
plugging in the value of t in the given equation.
h = -2 (3)^2 + 12 (3)
h =
18 m
This problem can also be solved graphically by plotting t
(x-axis) against h (y-axis). Then assigning values to t and calculate for h and
plot it in the graph to see the point in which the peak is obtained. Therefore
the answer to this is:
<span>The ball reaches a maximum height of 18
meters. The maximum of h(t) can be found both graphically or algebraically, and
lies at (3,18). The x-coordinate, 3, is the time in seconds it takes the ball
to reach maximum height, and the y-coordinate, 18, is the max height in meters.</span>
