Answer:
0.05 I hope that's correct:)
Answer:
The average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Step-by-step explanation:
We are given that
Standard deviation, 
ounces
We have to find the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag.
Assume the bag weight distribution is bell-shaped
Therefore,
We know that
Using the value of z
Now,
Hence, the average bag weight must be used to achieve at least 99 percent of the bags having 10 or more ounces in the bag=9.802
Since we’re trying to find minutes, concert all known information to minutes
1 hr 15 mins = 75 mins
1 hr 30 mins = 90 mins
Next, calculate how many total minutes Gage has skated in the first 8 days
75(5) + 90(3) = 645 mins
Create an equation to find the average of Gage’s minutes of skating. Add up all the minutes and divide by the total amount of days and set equal to 85, the average we are trying to get.
(645 mins + x mins)/9 days = 85
Solve for x
645 + x = 765
x = 120
So, in order to have an average of an 85 minute skate time, Gage would need to skate 120 minutes on the ninth day.
set up an equation for this. x will be the score of the losing team. x+2x=96. Then solve for x. 3x=96. x=96/3 x=32. So the losing team got 32 points and the winning team got 64
