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kotegsom [21]
2 years ago
11

Is there such thing as kidney insurance?

Mathematics
2 answers:
Ghella [55]2 years ago
6 0
That’s odd. I would think so.
masha68 [24]2 years ago
5 0
No . Unless you get a kidney transplant but most the time you only need 1 kidney
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Snezhnost [94]
Hm let's see the answer should be by the definition of isosceles triangle
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Seven more than double a number one is equal to five less than triple that number. What is that number?
Inga [223]

Answer:

-\frac{2}{5}

Step-by-step explanation:

7+2n=5-3n

2n+3n=5-7\\5n=-2\\n=-\frac{2}{5}

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The cookie recipe calls for 1/2 cup of flour to make 8 servings. How many cups of flour are needed to make 20 servings of cookie
Musya8 [376]
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Solve the system of equations
rewona [7]

Answer:

x = 1/4

y = -1/2

z = 9/4

Step-by-step explanation:

Here we have a system of 3 equations with 3 variables:

4*x + 2*y + 1 = 1

2*x - y = 1

x + 3*y + z = 1

The first step to solve this, is to isolate one of the variables in one of the equations, let's isolate "y" in the second equation:

2*x - y = 1

2*x - 1 = y

Now that we have an expression equivalent to "y", we can replace this in the other two equations:

4*x + 2*(2*x - 1) + 1 = 1

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Now let's simplify these two equations:

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7*x - 3 + z = 1

Now, in the first equation we have only the variable x, so we can solve that equation to find the value of x:

8*x - 1 = 1

8*x = 1 + 1 = 2

x = 2/8 = 1/4

Now that we know the value of x, we can replace this in the other equation to find the value of z.

7*(1/4) -3 + z = 1

7/4 - 3 + z = 1

z = 1 + 3 - 7/4

z = 4 - 7/4

z = 16/4 - 7/4 = 9/4

z = 9/4

Now we can use the equation y = 2*x - 1 and the value of x to find the value of y:

y = 2*(1/4) - 1

y = 2/4 - 1

y = 1/2 - 1

y = -1/2

Then the solution is:

x = 1/4

y = -1/2

z = 9/4

7 0
3 years ago
(5x-25)(x+4)=0<br> What’s the answer
NemiM [27]

Answer:

x = - 4, x = 5

Step-by-step explanation:

(5x - 25)(x + 4) = 0

Equate each factor to zero and solve for x

x + 4 = 0 ⇒ x = - 4

5x - 25 = 0 ⇒ 5x = 25 ⇒ x = 5

7 0
2 years ago
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