2 years ago

Create the equation of the line that passes through the point (1, -10) and is perpendicular to y=-1/3x+5

Mathematics

1 answer:

Ber [7]2 years ago

4 0

Answer:

y = 3x - 13

Step-by-step explanation:

y = -1/3x + 5

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of perpendicular line is 3

y = mx + b

y = 3x + b

Using (1,-10)

-10 = 3(1) + b

-10 = 3 + b

b = -13

y = 3x - 13

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Find the x- and y- intercepts of the line with the equation 3x+4y=-12

masya89 [10]

3x + 4y = -12

X - Intercept: 3x + 4y = -12
      3x + 4(0) = -12
           3x + 0 = -12
   3x = -12
      3    3
   x = -4
   (x, y) = (-4, 0)

Y - Intercept:   3x + 4y = 12
   3(0) + 4y = 12
   0 + 4y = 12
   4y = 12
      4 4
   y = 3
   (x, y) = (0, 3)

8 0

4 years ago

I need help I’m not sure

Daniel [21]

$\bf ~~~~~~~~~~~~\textit{middle point of 2 points } \\\\ (\stackrel{x_1}{3}~,~\stackrel{y_1}{5})\qquad (\stackrel{x_2}{-6}~,~\stackrel{y_2}{-6}) \qquad \left(\cfrac{ x_2 + x_1}{2}~~~ ,~~~ \cfrac{ y_2 + y_1}{2} \right) \\\\\\ \left( \cfrac{-6+3}{2}~~,~~\cfrac{-6+5}{2} \right)\implies \left(\cfrac{-3}{2}~~,~~\cfrac{-1}{2} \right)\implies \left( -1\frac{1}{2}~,~-\frac{1}{2} \right)$