All categories

2 years ago

Create the equation of the line that passes through the point (1, -10) and is perpendicular to y=-1/3x+5

Mathematics

1 answer:

Ber [7]2 years ago

4 0

Answer:

y = 3x - 13

Step-by-step explanation:

y = -1/3x + 5

Perpendicular lines have slopes that are negative reciprocals of one another

so slope of perpendicular line is 3

y = mx + b

y = 3x + b

Using (1,-10)

-10 = 3(1) + b

-10 = 3 + b

b = -13

y = 3x - 13

You might be interested in

Hey guys what is this type of equation/ question called 1 < x < 30

dimulka [17.4K]

Answer:

2,3,4,5,6,7,8,9,10,...29

Step-by-step explanation:

6 0

2 years ago

A club raised 80% of its goal for a charity. The club raised $1076. What was the goal?

4vir4ik [10]

Answer:

860.8

Step-by-step explanation:

6 0

2 years ago

What is the length of MN¯¯¯¯¯¯¯ ? Round to the nearest tenth of a unit. Enter your answer in the box. units Line segment on a co

notka56 [123]

I'm actually doing this quiz right now, so I'll let you know what the answer is.

6 0

2 years ago

Read 2 more answers

What is 7x^5-33x^4-4x^2+3x+52=0

lorasvet [3.4K]

7x^5-33x^4-4x^2+3x+52=

ANSWER: 7x^5 -33x^4 -4x^2+3x+52 (because there are no like terms)

5 0

3 years ago

Rationalize the denominator and simplify. StartFraction 5 minus StartRoot 3 EndRoot Over 4 plus 2 StartRoot 3 EndRoot EndFractio

nasty-shy [4]

Answer:

$\frac{13-7\sqrt{3}}{2}$

Step-by-step explanation:

We need to rationalize the denominator of $= \frac{5-\sqrt{3}}{4+2\sqrt{3}}$ . For rationalizing we multiply the equation by $\frac{4-2\sqrt{3}}{4-2\sqrt{3}}$

So, solving

$= \frac{5-\sqrt{3}}{4+2\sqrt{3}}*\frac{4-2\sqrt{3}}{4-2\sqrt{3}} \\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{4+2\sqrt{3}*4-2\sqrt{3}}\\=\frac{(5-\sqrt{3})(4-2\sqrt{3})}{(4)^2-(2\sqrt{3})^2}\\= \frac{5(4-2\sqrt{3})-\sqrt{3}(4-2\sqrt{3})}{16-(4*3)}\\=\frac{20-10\sqrt{3}-4\sqrt{3}+2*3}{16-12}\\=\frac{20+6-14\sqrt{3}}{4}\\=\frac{26-14\sqrt{3}}{4}\\= \frac{2(13-7\sqrt{3})}{4}\\=\frac{13-7\sqrt{3}}{2}$

5 0

3 years ago