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nata0808 [166]
3 years ago
11

Write an application that displays appropriate prompts to the user and reads a person

Computers and Technology
1 answer:
vfiekz [6]3 years ago
3 0

Answer:

The program to this question can be given as:

Program:

import java.util.*; //import package  

public class Person_detail //define class

{

public static void main(String ar[]) //define main function

{

String Name,hobby,dream_Job; //declare variable.

int age;

Scanner sc = new Scanner(System.in); //creating Scanner class object for user input.

System.out.print("Enter Your Name : "); //message  

name = sc.next(); //user input

System.out.print("Enter Your Age : ");

age = sc.nextInt();

System.out.print("Enter Your hobby: ");

hobby = sc.next();

System.out.print("Enter Your aim: ");

aim = sc.next();

//print values.

System.out.println("Hello, my name is "+name+" and I am "+age);

System.out.println("years old.My hobby is playing "+hobby+".");

System.out.println("I want to be a "+aim+" when I grow up!");

}

}

Output:

Hello, my name is XXX and I am 21

years old.My hobby is playing cricket .

I want to be a cricketer when I grow up!.

Explanation:

In the above program firstly we import the package for user input. Then we declare a class that is Person_detail. In this class, we declare the main function. In the main function, we declare a variable that is name, hobby, aim, and age. In these variable first 3 variables datatype is string and age variable data type in integer. Then we create a scanner class object and take input from the user and print it into a paragraph.

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Explanation:

Hope it helps

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Unlike when writing in a programming language, there are no set rules that must be followed when writing pseudocode. What do you
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Answer:

Explanation:

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3 years ago
Using the program below, explain what the output will be at LINE A. 1 #include 2#include 3#include 4 5 int value - 128; 6 7 int
slega [8]

Answer:

This is the complete correct program:

#include <stdio.h>

#include<sys/types.h>

#include<unistd.h>

int value = 128;

int main()

{

  pid_t pid;

  pid=fork();

  if (pid==0) /* child process */

  {

  value +=8;

  return 0; }

  else if (pid > 0) {/* parent process */

 wait (NULL);

 printf ("PARENT: value =%d\n" ,value); /* LINEA */

 return 0;

}

}

The output of the LINE A is:

PARENT: value = 128

Explanation:

The fork() function used in the program creates a new process and this process is the child process. The child process is same as the original process having its own address space or memory.

In the child process the value of pid is 0. So the if condition checks if pid==0. Then the child process adds 8 to the value of its variable according to the following statement  

value +=8;

Now the original process has value = 128. In else if part the parents process has the value of pid greater than zero and this portion of the program is of the parent process :

else if (pid > 0)

{ wait (NULL);

printf ("PARENT: value =%d\n" ,value);

return 0; }

So the value 128 is printed at the end in the output.

wait(NULL) is used to wait for the child process to terminate so the parent process waits untill child process completes.

So the conclusion is that even if the value of the variable pid is changed in the child process but it will not affect the value in the variable of the parent process.

5 0
3 years ago
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