Answer:
m∠A = 50°
m∠B = 70°
m∠C = 60°
Step-by-step explanation:
Determine the measure of angle A, B, and C in triangle ABC. If m∠A=(x-10)°,m∠B=(2x-50)°,and m∠C=x°
In a Triangle, the sum of the interior angles of a triangle = 180°
Step 1
We solve for x
Hence:
m∠A + m∠B + m∠C= 180°
(x-10)°+ (2x-50)°+ x° = 180°
x - 10 + 2x - 50 + x = 180°
4x - 60 = 180°
4x = 180° + 60°
4x = 240°
x = 240°/4
x = 60°
Step 2
Solving for each measure
x = 60°
m∠A=(x-10)°
= 60° - 10°
= 50°
m∠B=(2x-50)°
= 2(60)° - 50°
= 120° - 50°
= 70°
m∠C=x°
= 60°
A= 15+z+ square root 17(z+15)/ z-2
z=2a^2/(a-1)^2 + 30a/(a-1)^2 - 15/(a-1)^2
-4,-4 - 9,-1 is the answer, i think
Answer:
what you arest mine but the other one says no answer what
Step-by-step explanation: