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3 years ago

Help please no rush

Mathematics

1 answer:

s2008m [1.1K]3 years ago

6 0

To solve this, we take the number of subjects who weren't diabetic, and then divide them by the total number of subjects who took the test:

Probability = $\frac{28}{3+28}$
= $\frac{28}{31}$
= 0.903225..
= 0.90 (rounded)
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Answer:

So the probability of randomly selecting a subject who was not diabetic would be 0.90 (the final option)

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Note:
 We only used the numbers under 'Negative Test', because the question wanted the probability 'given that the test result was negative'

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Scores on the test are normally distributed with a mean of 79 and a standard deviation of 8.4. Find the numerical limits for a B

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This is not the question, the correct question is:

A humanities professor assigns letter grades on a test according to the following scheme. A: Top 6% of scores B: Scores below the top 6% and above the bottom 59% C: Scores below the top 41% and above the bottom 17% D: Scores below the top 83% and above the bottom 7% F: Bottom 7% of scores.

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Answer: The numerical limits for grade B is 81 and 92

Step-by-step explanation:

Given that

mean Ж = 79

Standard deviation S = 8.4

B: Scores below the top 6% and above the bottom 59%

To find the numerical value for Grade B

Below the top bottom 6% ( 0.06) is

p ( X < Ж ) = 1 - 0.06

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therefore

P( (X - ц)/S < (X - Ж) / S)) = 0.94

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