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3 years ago

Help please no rush

Mathematics

1 answer:

s2008m [1.1K]3 years ago

6 0

To solve this, we take the number of subjects who weren't diabetic, and then divide them by the total number of subjects who took the test:

Probability = $\frac{28}{3+28}$
= $\frac{28}{31}$
= 0.903225..
= 0.90 (rounded)
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Answer:

So the probability of randomly selecting a subject who was not diabetic would be 0.90 (the final option)

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Note:
 We only used the numbers under 'Negative Test', because the question wanted the probability 'given that the test result was negative'

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3 years ago

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> a<-rnorm(20,50,6)

> a

[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

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> sqrt(var(a))

[1] 7.470221

Step-by-step explanation:

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$X\sim N(\mu = 50, \sigma =6)$

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> a<-rnorm(20,50,6)

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[1] 51.72213 53.09989 59.89221 32.44023 47.59386 33.59892 47.26718 55.61510 47.95505 48.19296 54.46905

[12] 45.78072 57.30045 57.91624 50.83297 52.61790 62.07713 53.75661 49.34651 53.01501

Then we can find the mean and the standard deviation with the following formulas:

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[1] 50.72451

> sqrt(var(a))

[1] 7.470221

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