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tigry1 [53]
3 years ago
8

An inverted pyramid is being filled with water at a constant rate of 50 cubic centimeters per second. The pyramid, at the top, h

as the shape of a square with sides of length 8 cm, and the height is 15 cm. Find the rate at which the water level is rising when the water level is 3 cm.

Mathematics
2 answers:
Ipatiy [6.2K]3 years ago
7 0

Answer:

19.53125 cm/s

Step-by-step explanation:

h : s

15 : 8

s/h = 8/15

s = 8h/15

V = ⅓×s²×h

V = ⅓(8h/15)²×h = 64h³/675

dV/dh = 64h²/225

At h=3,

dV/dh = 64(3²)/225 = 64/25

dh/dV = 25/64

dV/dt = 50

dh/dt = dh/dV × dV/dt

= 25/64 × 50

= 19.53125 cm/s

klio [65]3 years ago
3 0

Step-by-step explanation:

Below is an attachment containing the solution.

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Answer:

1) w₁=4 - i w₂= -4 + i

2) w₁= 3 - i w₂= -3  + i

3) w₁= 1 + 2i w₂= - 1 - 2i

4) w₁= 2- 3i w₂= -2 + 3i

5) w₁= 5 - 2i w₂= -5 + 2i

6) w₁= 5 - 3i w₂= -5 + 3i

Step-by-step explanation:

The root of a complex number is given by:

\sqrt[n]{z}=\sqrt[n]{r}(Cos(\frac{\theta+2k\pi}{n}) + i Sin(\frac{\theta+2k\pi}{n}))

where:

r: is the module of the complex number

θ: is the angle of the complex number to the positive axis x

n: index of the root

1) z = 15 − 8i  ⇒ r=17 θ= -0.4899 rad

w₁=\sqrt{17}(Cos(\frac{-0.4899}{2}) + i Sin(\frac{-0.4899}{2}))=4-i

w₂=\sqrt{17}(Cos(\frac{-0.4899+2\pi}{2}) + i Sin(\frac{-0.4899+2\pi}{2}))=-1+i

2) z = 8 − 6i  ⇒ r=10 θ= -0.6435 rad

w₁=\sqrt{10}(Cos(\frac{ -0.6435}{2}) + i Sin(\frac{ -0.6435}{2}))= 3 - i

w₂=\sqrt{10}(Cos(\frac{ -0.6435+2\pi}{2}) + i Sin(\frac{ -0.6435+2\pi}{2}))= -3  + i

3) z = −3 + 4i  ⇒ r=5 θ= -0.9316 rad

w₁=\sqrt{5}(Cos(\frac{-0.9316}{2}) + i Sin(\frac{-0.9316}{2}))= 1 + 2i

w₂=\sqrt{5}(Cos(\frac{-0.9316+2\pi}{2}) + i Sin(\frac{-0.9316+2\pi}{2}))= -1 - 2i

4) z = −5 − 12i  ⇒ r=13 θ= 0.4426 rad

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w₂=\sqrt{13}(Cos(\frac{0.4426+2\pi}{2}) + i Sin(\frac{0.4426+2\pi}{2}))= -2 + 3i

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w₁=\sqrt{29}(Cos(\frac{-0.8098}{2}) + i Sin(\frac{-0.8098}{2}))= 5 - 2i

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w₂=\sqrt{34}(Cos(\frac{-1.0808+2\pi}{2}) + i Sin(\frac{-1.0808+2\pi}{2}))= -5 + 3i

6 0
3 years ago
In which number does the digit 2 have a value that is ten times as great as the value of the digit 2 in the number 135,284?
Valentin [98]

Answer: See explanation

Step-by-step explanation:

You didn't give the options but let me help out.

First and foremost, we should note that the value of the digit 2 in the number 135,284 is 200. Therefore, the value that is ten times as great as the value of the digit 2 in the number 135,284 would be:

= 10 × 200

= 2000

Therefore, the 2 must be in the thousands place. This can be seen in numbers such as:

172748.

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2 years ago
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gtnhenbr [62]
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snow_lady [41]
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