Point slope is y-y1=m(x-x1)
Keep y and x as they are (do not plug anything in for those).
Variable m is the slope.
x1 and y1 are part of the point, which is in (x, y) form.
With the information given, plug each into the equation.
m= 2 (It's the slope)
x1=-8
y1=5
Put these variables into the equation like this-
y-5=2(x--8)
The two negatives cancel out (between x and 8) so your final answer is-
y-5=2(x+8)
Answer:
3
4
4
3
4
4
3
5
5
3
4
5
5
4848
Step-by-step explanation:
hope I helped
A generic point on the graph of the curve has coordinates
The derivative gives us the slope of the tangent line at a given point:
Let k be a generic x-coordinate. The tangent line to the curve at this point will pass through 
and have slope 
So, we can write its equation using the point-slope formula: a line with slope m passing through 
has equation
In this case, 
and 
, so the equation becomes
We can rewrite the equation as follows:
We know that this function must give 0 when evaluated at x=0:
This equation has no real solution, so the problem looks impossible.
Step-by-step explanation:
are you sure you wrote the problem here correctly ?
because the distance will be 40km after less than half an hour just by the first car driving. way before the second car even starts.
to be precise, it would be after 60 minutes × 40 / 90
(= how many minutes of an hour are needed to reach 40km while going 90km/h) :
60 × 40 / 90 = 60 × 4 / 9 = 20 × 4 / 3 = 80/3 = 26.67 minutes.
but maybe the question was about 400km distance between the two cars.
so, the first car goes 90km/h for 2 hours.
at that moment it will be 2×90=180km ahead.
that would mean that 220km are still missing for the 400km assumption.
with each hour driving the first car makes 20km more than the second car.
to build up 220km that way would require
220/20 = 11 hours.
plus the 2 original head start hours this would make 13 hours as overall answer.
Answer: 10
Step-by-step explanation:
