All categories

2 years ago

Please help me with trigonometry and law of sines I’m being timed and really need the help

Mathematics

1 answer:

Usimov [2.4K]2 years ago

8 0

Step-by-step explanation:

cosA = AC² + BC²- AB² / 2 • AC • BC

cos A = 13.5²+23.9²-12.7²/2• 13.5 • 23.9

You might be interested in

Saturn is 8.867 × 108 miles away from the Sun. Uranus is 1.787 × 109 miles away from the Sun. Approximately how many times farth

GrogVix [38]

Answer:

0.2 times

Step-by-step explanation:

Saturn: 8.867 × 108 = 957.636

Uranus: 1.787 × 109 = 194.783

You take (Uranus: 194.783)

& you divide it by (Saturn: 957.636)

You should get a funky number like 0.203399830415732 but since they said approximately you only need to use the first 2 (don't forget to round)

That would make Uranus 0.2 times as far from the sun

4 0

2 years ago

Can 7:13 be simplified

gtnhenbr [62]

Answer:

no i don't think so

Step-by-step explanation:

7 0

3 years ago

Read 2 more answers

An airplane descends 2.8 miles to an elevation of 5.85 miles. Find the elevation of the plane before an airplane descends 2.2 mi

Natali5045456 [20]

Answer:

8.05 miles

Step-by-step explanation:

If it descended 2.2 miles to 5.85 miles then that means it was at 5.85 + 2.2 miles before its descent.

5.85 + 2.2 = 8.05

7 0

2 years ago

Read 2 more answers

Based on a study of population projections for 2000 to 2050, the projected population of a group of people (in millions) can b

Olegator [25]

Answer:

(a) 0.107 million per year

(b) 0.114 million per year

Step-by-step explanation:

$A(t) = 11.19(1.009)^t$

(a) The average rate of change between 2000 and 2014 is determined by dividing the difference in the populations in the two years by the number of years. In the year 2000, $t=0$ and in 2014, $t=14$ . Mathematically,

$\text{Rate}=\dfrac{A(2014) - A(2000)}{2014-2000}=\dfrac{11.19(1.009)^14-11.19(1.009)^0} {14}$

$A(0)=\dfrac{12.69-11.19}{14}=\dfrac{1.5}{14}=0.107$

(b) The instantaneous rate of change is determined by finding the differential derivative at that year.

The result of differentiating functions of the firm $y=a^x$ (where $a$ is a constant) is $\dfrac{dy}{dx}=a^x\ln a$ . Let's use in this in finding the derivative of $A(t)$ .