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jenyasd209 [6]
4 years ago
15

On a six-question multiple-choice test there are five possible answers for each question, of which one is correct (C) and four a

re incorrect (I). If a student guesses randomly and independently, find the probability of (a) Being correct only on questions 1 and 4 (i.e., scoring C, I, I, C, I, I). (b) Being correct on two questions.
Mathematics
1 answer:
Anon25 [30]4 years ago
5 0

Answer:

(a) 1.64%

(b) 24.58%

Step-by-step explanation:

As for each question there are one correct answer in five possible answers, the probability of guessing the correct answer is 1/5 = 0.2, so the probability of guessing the wrong answer is (1 - 0.2) = 0.8.

(a) The probability of being correct only on questions 1 and 4 is calculated multiplying all the following probabilities:

question 1 correct: 0.2

question 2 wrong: 0.8

question 3 wrong: 0.8

question 4 correct: 0.2

question 5 wrong: 0.8

question 6 wrong: 0.8

P = (0.2)^2 * (0.8)^4 = 0.0164 = 1.64%

(b) The probability of being correct in two questions is calculated similarly to the question in (a), but now we also have a combination problem: The 2 correct questions can be any group of 2 questions inside the 6 total questions, so we also multiply the probability of each question being correct or wrong by the combination of 6 choose 2:

C(6,2) = 6!/(4!*2!) = 6*5/2 = 15

P = 15 * (0.2)^2 * (0.8)^4 = 0.2458 = 24.58%

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Step-by-step explanation:

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The function f(x) = x2 has been translated 9 units up and 4 units to the right to form the function g(x). Which represents g(x)?
Alenkinab [10]

For this case, the parent function is given by:

f (x) = x ^ 2

We apply the following transformations:


Vertical translations:

Suppose that k> 0

To graph y = f (x) + k, move the graph of k units upwards:

For k = 9 we have:

h (x) = x ^ 2 + 9


Horizontal translations:

Suppose that h> 0

To graph y = f (x-h), move the graph of h units to the right

For h = 4 we have:

g (x) = (x-4) ^ 2 + 9

Answer:

The function g (x) is given by:

g (x) = (x-4) ^ 2 + 9

7 0
3 years ago
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the exit to garrett's house is after exit 51 but before exit 62. the number on the exit sing is not a prime nunber. the number i
Alex Ar [27]
52
- is prime? No
- is multiple of 3? No
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53
- is prime? Yes
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54
- is prime? No
- is multiple of 3? Yes
- is multiple of 4? No
continue

55
- is prime? No
- is multiple of 3? No
continue

56
- is prime? No
- is multiple of 3? No
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57
- is prime? No
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58
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59
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60
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Therefore 60 is the answer, as it fits all the conditions


Simple trial and error.
5 0
4 years ago
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Lindsey Wilson was the top scorer in a women's professional basketball league for the 2006 regular season, with a total of 814 p
baherus [9]

Answer:

The number of free throws, two-point throw, and three-point throw are 135, 173, and 111 respectively.

Step-by-step explanation:

Let x,y, and z are the numbers of two-point field goals, numbers of three-point field goals, and the number of free-throws (one-point goal) respectively.

The total points= 814

\Rightarrow 2x+3y+z=814\;\cdots(i)

As the number of two-point  goals was 49 less than double the number of three-point field goals she made.

\Rightarrow x=2y-49 \;\cdots(ii)

Again, the number of free goals was 38 less than the number of two-point field goals she made.

\Rightarrow z=x-38\;\cdots(iii)

From equations (i) and (iii)

2x+3y+x-38=814

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From equation (ii),

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From equation (iii),

z=173-38=135.

Hence,

The number of free throws, z= 135

The number of two-point throw, x=173

The number of three-point throw, y=111.

3 0
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