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Zinaida [17]
3 years ago
5

Which graph represents the solution set of the inequality x + 2 greater-than-or-equal-to 6

Mathematics
2 answers:
Iteru [2.4K]3 years ago
6 0

Answer:

x ≥ 4; solid circle at 4 and shaded to the right

Tanzania [10]3 years ago
5 0

Answer:

  x ≥ 4; solid circle at 4 and shaded to the right

Step-by-step explanation:

Given:

  x +2 ≥ 6

Subtract 2

  x +2 -2 ≥ 6 -2

  x ≥ 4

This is graphed as a solid circle at x=4 and shaded to the right (where x > 4).

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Use the strategy to simplify 4\sqrt(576)<br> Write the prime factorization of the radicand.
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<h3>Answer:   96</h3>

===================================================

Work Shown:

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2 years ago
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Answer:

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The daily temperatures in fall and winter months in Virginia have a mean of 62°F. A meteorologist in southwest
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2 years ago
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Points P and Q belong to segment AB . If AB = a, AP = 2PQ = 2QB, find the distance: midpoints between AP QB
Digiron [165]

Answer: The distace between midpoints of AP and QB is \frac{a}{8}.

Step-by-step explanation: Points P and Q are between points A and B and the segment AB measures a, then:

AP + PQ + QB = a

According to the question, AP = 2 PQ = 2QB, so:

PQ = \frac{AP}{2}

QB = \frac{AP}{2}

Substituing:

AP + 2*(\frac{AP}{2}) = a

2AP = a

AP = \frac{a}{2}

Since the distance is between midpoints of AP and QB:

2QB = AP

QB = \frac{AP}{2}

QB = \frac{a}{2}*\frac{1}{2}

QB = \frac{a}{4}

MIdpoint is the point that divides the segment in half, so:

<u>Midpoint of AP</u>:

\frac{AP}{2} = \frac{a}{2}*\frac{1}{2}

\frac{AP}{2} = \frac{a}{4}

<u>Midpoint of QB</u>:

\frac{QB}{2} = \frac{a}{4}*\frac{1}{2}

\frac{QB}{2} = \frac{a}{8}

The distance is:

d = \frac{a}{4} - \frac{a}{8}

d = \frac{a}{8}

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3 years ago
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