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Solnce55 [7]
3 years ago
6

Generate a frequency table for the following data: 3, 12, 25, 2, 3, 6, 17, 17, 15, 13, 20, 22, 21, 18, 19.

Mathematics
1 answer:
Mars2501 [29]3 years ago
3 0
It is letter “A”
Hope this helps
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Payton has 2 pizzas. each pizza is cut into 10 equal slices. she and her friends eat 14 slices. what part of the pizzas did they
kakasveta [241]
14 / 20 total slices = 7 / 10, which is 0.7 if you're looking for a decimal.
That's 70% of the pizza, which I would eat by myself.
3 0
3 years ago
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Find the length of B to the nearest tenth using the Pythagorean theorem.​
bekas [8.4K]

Step-by-step explanation:

Here

BC=P=10

AC=B=b

AB=H=15

then using fourmula

h^2= p^2+ b^2

b^2= 15×15 - 10× 10

b^2= 125

b=11.2

4 0
3 years ago
Does anyone know the answer?I am stuck? Please explain it to me!
9966 [12]
We are given the length of AC and AB to be 20 and 6, respectively, so we can subtract 6 from 20 to find BC to be 14 cm.

The circumference of a circle is equal to 2 \pi r

C=2 \pi (14) = 28 \pi

The answer is approximately 87.96 cm
7 0
3 years ago
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The Summer Olympics were held in St. Louis 92 years before the Summer Olympics were held in Atlanta. In what year were the Olymp
andrezito [222]
1904 write if not just subtract 92 from 96 and you have your answer hope that helps
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3 years ago
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A triangle has vertices at (1,10), (-5,2), and (7,2). What is its orthocenter. Show your work.
kondor19780726 [428]

Answer:

Question: What is the orthocenter of a triangle with the vertices (-1,2) (5,2) and (2,1)?

The coordinates of point A are (-1,2), point B are (5,2), and point C are (2,1).

The orthocent is the intersection of the three altitudes. An altitude goes from a vertex and is perpendicular to the line containing the opposite side.

In the coordinate plane the equations of the altitudes can be found and then a system of equations can be solved.

Altitude 1. From point C perpendicular to the line containing side AB.

Slope of line AB is 0 (horizontal line), a vertical line is perpendicular to a horizontal line. Thus, the equation of altitude 1 is  x=2 .

Altitude 2. From point B perpendicular to the line containing side AC.

Slope of line AC is  −13 , the slope of a line perpendicular to line AC is 3. The equation of altitude 2 is  y=3x−13  

Altitude 3. From point A perpendicular to the line containing side BC.

Slope of line BC is  13 , the slope of a line perpendicular to line BC is  −3 . The equation of altitude 3 is  y=−3x−1  

The orthocenter is the point where all three altitudes intersect.

x=2  

y=3x−13  

y=−3x−1  

Use substitution to solve the first two equations  y=3(2)−13=−7  

The orthocenter is the point  (2,−7)  

we did not need the third equation, but we can use it as a check, plug the coordinates into the third equation:

−7=−3(2)−1  

−7=−6−1  

−7=−7  it works.

3 0
3 years ago
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