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Feliz [49]
4 years ago
8

Find the area of the missing piece of the polygon and explain your process for finding it:

Mathematics
1 answer:
rusak2 [61]4 years ago
6 0

Answer:

The area of the polygon is 42cm^{2}.

Step-by-step explanation:

A polygon is a shape that has three or more sides. They are named with respect to the number of their sides. Example, an octagon has 8 sides, hexagon has 6 sides etc.

From the given figure, the area of the shaded polygon can be calculated by;

Area of polygon = Area of square - Sum of areas given

Sum of areas given = 24 + 30 + 48

                                = 102cm^{2}

The four sides of the figure are equal, thus it is a square. The length of each side is 12 cm, so that:

Area of square = length × width

                        = 12 × 12

                       = 144cm^{2}

Area of polygon = 144 - 102

                           = 42cm^{2}

The area of the polygon is 42cm^{2}.

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Whats the answer to this ?
8090 [49]

Answer: 312 ft^{2}

Step-by-step explanation:

Area of Rectangle = bh = 16 ft x 18 ft  = 288 ft^{2}

Area of Triangle = 1/2 bh = 1/2 x (16-12) ft x (6) ft x 2 (There's 2 triangles) = 24 ft^{2}

24 ft^2 + 288 ft^2 = 312 ft^2

8 0
3 years ago
1/29+12/58+12/29=
irakobra [83]
Just find a common denominator and find the smallest number that goes into it, which in this case it is 29, so
1/29+6/29+12/29=19/29
5 0
3 years ago
I AM GIVING 45 POINTS TO WHOEVER GETS THIS RIGHT... plz answer corectly and try... i was working on this for sooo long. Plz try
Alexxx [7]
When you have 3 choices for each of 6 spins, the number of possible "words" is
  3^6 = 729

The number of permutations of 6 things that are 3 groups of 2 is
  6!/(2!×2!×2!) = 720/8 = 90

A) The probability of a word containing two of each of the letters is 90/729 = 10/81


The number of permutations of 6 things from two groups of different sizes is
  (2 and 4) : 6!/(2!×4!) = 15
  (3 and 3) : 6!/(3!×3!) = 20
  (4 and 2) : 15
  (5 and 1) : 6
  (6 and 0) : 1

B) The number of ways there can be at least 2 "a"s and no "b"s is
  15 + 20 + 15 + 6 + 1 = 57
The probability of a word containing at least 2 "a"s and no "b"s is 57/729 = 19/243.


_____
These numbers were verified by listing all possibilities and actually counting the ones that met your requirements.
6 0
3 years ago
tank a contains 35 gallons of water and is increasing at a rate of 5 gallons per minute. tank b contains 100 gallons of water bu
julia-pushkina [17]
A=35+5t, b=100-8t, a=b when:

35+5t=100-8t subtract 35 from both sides

5t=65-8t  add 8t to both sides

13t=65  divide both sides by 13

t=5 minutes

a=35+5(5)=60 gallons

So the tanks have an equal volume of 60 gallons after five minutes.


4 0
4 years ago
Does xy+7y=1 define x? Yes or no?
Nina [5.8K]

Answer:

Yes it is, You can rearrange the expression to find that  y is uniquely determined in terms of  x, therefore a function.

Step-by-step explanation:

6 0
3 years ago
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