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Artist 52 [7]
3 years ago
10

A robot can complete 5 tasks in 2/3 hour. Each task takes the same amount of time.

Mathematics
2 answers:
Natasha2012 [34]3 years ago
7 0

Answer:

5 tasks = 2/3 hour.

1 task = 2/3 hour /5 = 2/15 hour.

How many tasks can the robot complete in one hour?

1 hour / (2/15 hour/task) = 15/2 tasks = 7.5 tasks.

earnstyle [38]3 years ago
4 0

Answer:

A. 8 Minutes  

B. 7.5 Tasks

Step-by-step explanation:

A. Since 2/3 of an hour is 40 minutes. We can divide 40 by 5 to get the answer of 8 minutes per task.

B. An hour is 60 minutes. So 60 divided by 8 minutes would be 7.5 Tasks.

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Ber [7]
.004052
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76255) 309.00000
305.020
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4.98000
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1.16725




5 0
3 years ago
Harry and John share £60 in the ratio of 2: 1 work out how much money Harry gets ​
krek1111 [17]

Answer:

40

Step-by-step explanation:

3u-> 60

1u-> 20

2u->40

6 0
3 years ago
Find the product -1.2(0.04)
patriot [66]

Answer:

-0.048

Step-by-step explanation:

-1.2 * 0.04 = -1.2 * 4 / 100 = -4.8 / 100 = -).048

4 0
2 years ago
Please help me. these problems<br>​
jeyben [28]

Answer:

1st problem:

Converges to 6

2nd problem:

Converges to 504

Step-by-step explanation:

You are comparing to \sum_{k=1}^{\infty} a_1(r)^{k-1}

You want the ratio r to be between -1 and 1.

Both of these problem are so that means they both have a sum and the series converges to that sum.

The formula for computing a geometric series in our form is \frac{a_1}{1-r} where a_1 is the first term.

The first term of your first series is 3 so your answer will be given by:

\frac{a_1}{1-r}=\frac{3}{1-\frac{1}{2}}=\frac{3}{\frac{1}{2}=6

The second series has r=1/6 and a_1=420 giving me:

\frac{420}{1-\frac{1}{6}}=\frac{420}{\frac{5}{6}}=420(\frac{6}{5})=504.

3 0
3 years ago
find the values of x and y that make these triangles congruent by the hl theorem x=2,y=3 x=-2,y=3x=3,y=2x=4,y=8
AnnyKZ [126]

Answer:

The correct option is x=3 , y=2

Step-by-step explanation:

According to the HL theorem if the hypotenuse and one leg of a right triangle are congruent to the hypotenuse and one leg of another right triangle then the triangles are congruent.

By using this theorem we can set up the system of equations as follows:

x=y+1 ...(1)

2x+3= 3y + 3 ..(2)

Now we will plug the value y+1 of equation 1 in equation 2.

2x+3 = 3y+3

2(y+1)+3=3y+3

2y+2+3=3y+3

2y+5=3y+3

Now combine the like terms:

5-3=3y-2y

2=y

y=2

Now plug the value y=2 in equation 1.

x=y+1

x=2+1

x=3

Thus the values of(x.y) are{(2,3)}

Therefore the correct option is x=3 , y=2 .....

3 0
3 years ago
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