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k0ka [10]
3 years ago
8

Please help with 2. 3. and 4.

Mathematics
2 answers:
Y_Kistochka [10]3 years ago
6 0

Answer:

2. Since it is equilateral, we just set up an equation with using any two sides (since they are all equal)

12x - 22 = 10x - 6

12x - 10x - 22 = -6

2x - 22 = -6

2x = 22 - 6

2x = 16

x = 16/2

x = 8

Each side = 74

3. Same formula for this. Get any two sides and setup the equation.

4x - 25 = x + 14

4x - x - 25 = 14

3x = 25 + 14

3x = 39

x = 39/3

x = 13

Each side = 27

4. This one is also simple. Since DE = EF. We substitute its sides with the equations.

8x - 13 = 5x + 17

8x - 5x - 13 = 17

3x - 13 = 17

3x = 17 + 13

3x = 30

x = 30/3

x = 10

DE and EF = 67

DF = 31

Mashcka [7]3 years ago
5 0

Answer:

Step-by-step explanation:

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A boat travel 312 miles each way downstream and back. The trip downstream took 13 hours. the trip back took 26 hours. What is th
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Remember that Speed= \frac{distance}{time}. Since the distance of the complete trip is 312 miles, the distance of each way is \frac{312}{2} =156 miles. 
Let  S _{b} be the speed of the boat in still water and S_{c} the speed of the current.

Now, for the downstream trip the boat is traveling with the current, so:
S_{b} +S_{c} = \frac{156}{13}
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For the trip back the boat is traveling against the current, so:
S _{b} -S_{c} = \frac{156}{26}
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Next, lets add equation (1) and equation (2) to get rid of S _{c}:
\left \{ {{S_{b}+S_{c}  =12} \atop {+(S_{b}-S_{c}  =6})} \right.
2S_{b} =18
S _{b} = \frac{18}{2}
S _{b} =9

Finally, now that we know the speed of the boat in still water, lets replace that value in our equation (1) to find the speed of the current:
9+S_{c} =12
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We can conclude that the speed of the boath in still water is 9\frac{mi}{h}, and the current of the stream is 3\frac{mi}{h}.


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4 years ago
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