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Mariana [72]
3 years ago
11

Steve determines that sides DK and BC are congruent. He also measures angle K and angle C and determines that they are congruent

He concludes that the triangles are congruent by the SAS Congruence Theorem. Is Steve correct? If he is incorrect, which congruence theorem should Steve use? Explain your reasoning and show all of your work including measurement of angles and / o * r line segments .
Mathematics
1 answer:
JulijaS [17]3 years ago
6 0

Answer:

See below

Step-by-step explanation:

SAS requires two sides and the included angle to be congruent

Steve needs to measure sides EK and AC and if they are congruent, he can then complete his proof

<u>Let's find the measure of EK and AC</u>

  • EC = \sqrt{(-4-4)^2 + (0-6)^2} = \sqrt{8^2 + 6^2}  = \sqrt{100} = 10\\
  • AC = \sqrt{(-2 - 6)^2 + (9 - 3)^2} = \sqrt{8^2 + 6^2} = \sqrt{100} = 10

As we see EK = AC = 10, so the proof is complete

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Step-by-step explanation:

<u><em>The complete question is</em></u>

A cone and a triangular pyramid have a height of 9.3 m  and their cross-sectional areas are equal at every level  parallel to their respective bases. The radius of the base of the cone is 3 in and the other leg (not x) of the triangle base of the triangular pyramid is 3.3 in

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The picture of the question in the attached figure

we know that

If their cross-sectional areas are equal at every level  parallel to their respective bases and the height is the same, then their volumes are equal

Equate the volume of the cone and the volume of the triangular pyramid

\frac{1}{3}\pi r^{2}H=\frac{1}{3}[\frac{1}{2}(b)(h)H]

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\pi r^{2}=\frac{1}{2}(b)(h)

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r=3\ in\\b=3.3\ in\\h=x\ in\\pi=3.14

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(3.14)(3)^{2}=\frac{1}{2}(3.3)(x)

solve for x

28.26=\frac{1}{2}(3.3)(x)

x=28.26(2)/3.3\\x=17.1\ in

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