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3 years ago

Lines p and q are parallel. Solve for x.

Mathematics

2 answers:

Murljashka [212]3 years ago

7 0

Answer:

X=52

Step-by-step explanation:

3X+24=180

3X=180-24

3X=156

X=156/3

X=52

harina [27]3 years ago

4 0

Answer:

3 x + 24

Step-by-step explanation:

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Solve for x.

exis [7]

Answer:

11.2

Step-by-step explanation:

tan( <em>angle </em>) = <em>opposite / adjacent</em>

8 0

3 years ago

Plsss someone help me pls!!! PART B: identify congruent angles

Westkost [7]

Answer:

∠R=∠C

∠U=∠A

∠G=∠R

∴∠RUG=∠CAR

6 0

3 years ago

Find f-1(x), if f(x) = 3x – 6. Justify your

Sergio039 [100]

Answer: 1/3 (x + 6)

Explanation: given f(x) = 3x - 6.
Let y = f(x) and so y = 3x - 6.
Trade places between x and y.
x = 3y - 6
Solve for y
x + 6 = 3y
y = x + 6/3
Now the new y is the inverse and so y = f-1(x)
f-1(x) = 1/3(x + 6)

4 0

3 years ago

(a) Find the size of each of two samples (assume that they are of equal size) needed to estimate the difference between the prop

zalisa [80]

Answer:

(a) The sample sizes are 6787.

(b) The sample sizes are 6666.

Step-by-step explanation:

(a)

The information provided is:

Confidence level = 98%

MOE = 0.02

n₁ = n₂ = n

$\hat p_{1} = \hat p_{2} = \hat p = 0.50\ (\text{Assume})$

Compute the sample sizes as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{2\times\hat p(1-\hat p)}{n}$

$n=\frac{2\times\hat p(1-\hat p)\times (z_{\alpha/2})^{2}}{MOE^{2}}$

$=\frac{2\times0.50(1-0.50)\times (2.33)^{2}}{0.02^{2}}\\\\=6786.125\\\\\approx 6787$

Thus, the sample sizes are 6787.

(b)

Now it is provided that:

$\hat p_{1}=0.45\\\hat p_{2}=0.58$

Compute the sample size as follows:

$MOE=z_{\alpha/2}\times\sqrt{\frac{\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})}{n}$

$n=\frac{(z_{\alpha/2})^{2}\times [\hat p_{1}(1-\hat p_{1})+\hat p_{2}(1-\hat p_{2})]}{MOE^{2}}$

$=\frac{2.33^{2}\times [0.45(1-0.45)+0.58(1-0.58)]}{0.02^{2}}\\\\=6665.331975\\\\\approx 6666$

Thus, the sample sizes are 6666.

7 0

3 years ago

I miss the equation, point D.

Maru [420]

The answer is : Sn = S(n-1) + n

7 0

3 years ago