Answer:
what grade us it maybe u can help you but if I cant I'm sorru
Step-by-step explanation:
How are we supposed to help...?
CL.1.142):
A):
x5 ==> 4 boxes = 3ft <==== x5
20 boxes = ? ft
20 boxes is 15 ft. high
B): x3 ===> 4 boxes = 3ft. <==== x3
? boxes = 9ft.
12 boxes will fit in one stack.
c): CL.143
Perimeter = 15 + 29 + 9 + 11 + 6 + 18 =====> 88m
A1 = b * h
(18)(15)
270m^2
A2 = b * h
(11)(9)
99
Total Area ======> 270 + 99 ======> 369m^2
CL.1-144
1/4 + 1/4 + 1/5 = 5/20 + 5/20 + 4/20 ====> 14/20
1/4 * 5/5 =====> 5/20
1/5 * 4/4 =====> 4/20
14/20 + ?/20 = 20/20
? = 6 Missing Section
6/20 ======> 3/10
CL-1.145
A): 40/100 = 4/10 ====> 2/5
0.4 ========> 40%
B): 1/6 ======> .00000
0.16 (Repeating 6) ======> 16.6%
C): 37.5/100 = 375/1000 =======> 3/8
0.375 =========> 37.5%
CL-1.146
ADD: 1/6 + 1/2 show all steps:
1/6 + 1/2
1/6 + 3/6
1 + 3 / 6
4/6 =======> 2/3 =======> Decimal: =======> 0.666667
Hope that helps!!!! : )
Complete question :
Suppose that of the 300 seniors who graduated from Schwarzchild High School last spring, some have jobs, some are attending college, and some are doing both. The following Venn diagram shows the number of graduates in each category. What is the probability that a randomly selected graduate has a job if he or she is attending college? Give your answer as a decimal precise to two decimal places.
What is the probability that a randomly selected graduate attends college if he or she has a job? Give your answer as a decimal precise to two decimal places.
Answer:
0.56 ; 0.60
Step-by-step explanation:
From The attached Venn diagram :
C = attend college ; J = has a job
P(C) = (35+45)/300 = 80/300 = 8/30
P(J) = (30+45)/300 = 75/300 = 0.25
P(C n J) = 45 /300 = 0.15
1.)
P(J | C) = P(C n J) / P(C)
P(J | C) = 0.15 / (8/30)
P(J | C) = 0.5625 = 0.56
2.)
P(C | J) = P(C n J) / P(J)
P(C | J) = 0.15 / (0.25)
P(C | J) = 0.6 = 0.60