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3 years ago

Identify the figure formed with two square bases and four rectangular lateral faces

2 answers:

4 0

The shape formed by two square bases and four rectangles is a rectangular prism. In this shape, four sides are the same, and the two squares on the end are also the same

Anastasy [175]3 years ago

3 0

The correct answer is:

This is a rectangular prism.

Explanation:

A prism is a three-dimensional figure with two congruent, parallel bases connected by a height. If this were a cube, all of the faces, the bases and lateral faces, would be squares.

However, in this figure, the lateral faces are rectangles; this makes it a rectangular prism.

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In the following equation, a and b are both integers. a(3x-8)=b -18x

almond37 [142]

A = -6
b = 48
Hope this helps :)

3 0

3 years ago

Suppose X, Y, and Z are random variables with the joint density function f(x, y, z) = Ce−(0.5x + 0.2y + 0.1z) if x ≥ 0, y ≥ 0, z

dexar [7]

Answer:

The value of the constant C is 0.01 .

Step-by-step explanation:

Given:

Suppose X, Y, and Z are random variables with the joint density function,

$f(x,y,z) = \left \{ {{Ce^{-(0.5x + 0.2y + 0.1z)}; x,y,z\geq0 } \atop {0}; Otherwise} \right.$

The value of constant C can be obtained as:

$\int_x( {\int_y( {\int_z {f(x,y,z)} \, dz }) \, dy }) \, dx = 1$

$\int\limits^\infty_0 ({\int\limits^\infty_0 ({\int\limits^\infty_0 {Ce^{-(0.5x + 0.2y + 0.1z)} } \, dz }) \, dy } )\, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y }(\int\limits^\infty_0 {e^{-0.1z} } \, dz }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0{e^{-0.2y}([\frac{-e^{-0.1z} }{0.1} ]\limits^\infty__0 }) \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}([\frac{-e^{-0.1(\infty)} }{0.1}+\frac{e^{-0.1(0)} }{0.1} ]) } \, dy }) \, dx = 1$

$C\int\limits^\infty_0 {e^{-0.5x}(\int\limits^\infty_0 {e^{-0.2y}[0+\frac{1}{0.1}] } \, dy }) \, dx =1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2y} }{0.2}]^\infty__0 }) \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}([\frac{-e^{-0.2(\infty)} }{0.2}+\frac{e^{-0.2(0)} }{0.2}] } \, dx = 1$

$10C\int\limits^\infty_0 {e^{-0.5x}[0+\frac{1}{0.2}] } \, dx = 1$

$50C([\frac{-e^{-0.5x} }{0.5}]^\infty__0}) = 1$

$50C[\frac{-e^{-0.5(\infty)} }{0.5} + \frac{-0.5(0)}{0.5}] =1$

$50C[0+\frac{1}{0.5} ] =1$

$100C = 1$ ⇒ $C = \frac{1}{100}$

C = 0.01

3 0

2 years ago

The prism shown has a volume of 798 cm3.

a_sh-v [17]

Answer:

10.5 cm

Step-by-step explanation:

Volume = base area × height

798 = (9.5 × 8) × height

height = 798/76

height = 10.5

4 0

3 years ago

PLEASE HELP!!!

erastovalidia [21]

Step-by-step explanation:

to write a line equation we need minimum of two points. basicaly a line is written in the form y=mx+c where, m is the slope of the line and c is the intercept made by the line on x-axis (OR) or if two points (x1,y1) and (x2,y2) are given then we can form a line equation as (y-y1)= (y2-y1)*1/(x2-x1) *x-x1 (OR) (y-y2)= (y2-y1)*1/(x2-x1) *x-x2

7 0

2 years ago

Plz hellppppp me u won’t regret it

nexus9112 [7]

Answer:

Area of circle = 200.96 units²

Step-by-step explanation:

The formula to find the area of a circle is: πr², where r is the radius (which is half of the diameter)

So the diameter is 16 and of 16 is 8, which is the radius.

Sub it into the formula of a circle and you would get the area of a circle.

3.14 x 8²

Use calculator

Area of circle = 200.96 units²

8 0

2 years ago