The probability of getting two red lenses when two are selected will be 2/13.
<h3>What is probability?</h3>
The probability of favorable events to the total number of occurrences.
A box contains four red, three blue, and six green lenses.
Two lenses are randomly selected from the box.
Then the probability of getting two red lenses when two are selected if the first selection is not replaced before the second selection is made will be
The total number of the event will be
Total event = ¹³C₂
Total event = 78
Then the favorable event will be
Favorable event = ⁴C₁ x ³C₁
Favorable event = 4 x 3 = 12
Then we have
P = 12 / 78
P = 2/13
More about the probability link is given below.
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Answer:
z = 83 / (- c + 6 - t)
Step-by-step explanation:
Given:
-cz+ 6z = tz + 83
z=?
-cz+ 6z = tz + 83
Collect like terms
-cz+ 6z - tz = 83
Factorize
z(- c + 6 - t) = 83
Divide both sides by (- c + 6 - t)
z(- c + 6 - t) / (- c + 6 - t) = 83 / (- c + 6 - t)
z = 83 / (- c + 6 - t)
Answer:
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Step-by-step explanation:
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Answer:
The correct answer is option D: 
Step-by-step explanation:
Given:
log(y)= 3.994
Solution:
A logarithm base b of a positive number x satisfies the following definition:
For 
Also if no base b is indicated, the base of the logarithm is assumed to be 10
.
Thus, in log(y)= 3.994 base b is not indicated. so its base is assumed to be 10
now
Then
